题目内容
(2011?郑州模拟)能简算的要简算:
(1)432×99-568
(2)14
÷4-(3+5÷9)
(3)51×68×78÷(17×34×13)
(4)1
×(2
-0.75)+15
÷
.
(1)432×99-568
(2)14
| 2 |
| 9 |
(3)51×68×78÷(17×34×13)
(4)1
| 4 |
| 17 |
| 2 |
| 3 |
| 1 |
| 2 |
| 17 |
| 21 |
分析:算式(1)可据凑整法将432×99变为432×(100-1)后再据一个数减两个数等于减去这两个数的和的减法性质进行计算;
算式(2)按四则混合运算的运算顺序计算即可;
算式(3)可根据一个数除以几个数的积等于将这几个数分别相除的除法性质及乘法交换律及结合律进行计算;
算式(4)可据乘法分配律进行计算.
算式(2)按四则混合运算的运算顺序计算即可;
算式(3)可根据一个数除以几个数的积等于将这几个数分别相除的除法性质及乘法交换律及结合律进行计算;
算式(4)可据乘法分配律进行计算.
解答:解:(1)432×99-568
=432×(100-1)-568,
=432×100-432-568,
=43200-(432+568),
=43200-1000,
=42200;
(2)14
÷4-(3+5÷9)
=
×
-(3+
),
=
-
,
=0;
(3)51×68×78÷(17×34×13)
=51×68×78÷17÷34÷13,
=(51÷17)×(68÷34)×(78÷13),
=3×2×6,
=36;
(4)1
×(2
-0.75)+15
÷
.
=
×(
-
)+
×
,
=
×
+
×
,
=(
+
)×
,
=(
+
)×
,
=
×
,
=
.
=432×(100-1)-568,
=432×100-432-568,
=43200-(432+568),
=43200-1000,
=42200;
(2)14
| 2 |
| 9 |
=
| 128 |
| 9 |
| 1 |
| 4 |
| 5 |
| 9 |
=
| 32 |
| 9 |
| 32 |
| 9 |
=0;
(3)51×68×78÷(17×34×13)
=51×68×78÷17÷34÷13,
=(51÷17)×(68÷34)×(78÷13),
=3×2×6,
=36;
(4)1
| 4 |
| 17 |
| 2 |
| 3 |
| 1 |
| 2 |
| 17 |
| 21 |
=
| 21 |
| 17 |
| 8 |
| 3 |
| 3 |
| 4 |
| 31 |
| 2 |
| 21 |
| 17 |
=
| 21 |
| 17 |
| 23 |
| 12 |
| 31 |
| 2 |
| 21 |
| 17 |
=(
| 23 |
| 12 |
| 31 |
| 2 |
| 21 |
| 17 |
=(
| 23 |
| 12 |
| 186 |
| 12 |
| 21 |
| 17 |
=
| 209 |
| 12 |
| 21 |
| 17 |
=
| 1463 |
| 68 |
点评:算式(4)中的数据较为复杂,计算时要细心,注意通分、约分.
练习册系列答案
相关题目