题目内容
解方程.
x=16
x÷
=
x÷
=12.
| 2 |
| 17 |
x÷
| 4 |
| 9 |
| 15 |
| 16 |
| 2 |
| 3 |
| 1 |
| 4 |
分析:(1)依据等式的性质,方程两边同时除以
求解,
(2)依据等式的性质,方程两边同时乘
求解,
(3)依据等式的性质,方程两边同时乘
,再同时除以
求解.
| 2 |
| 17 |
(2)依据等式的性质,方程两边同时乘
| 4 |
| 9 |
(3)依据等式的性质,方程两边同时乘
| 1 |
| 4 |
| 2 |
| 3 |
解答:解:(1)
x=16,
x÷
=16÷
,
x=136;
(2)x÷
=
,
x÷
×
=
×
,
x=
;
(3)
x÷
=12,
x÷
×
=12×
,
x÷
=3÷
,
x=4.5.
| 2 |
| 17 |
| 2 |
| 17 |
| 2 |
| 17 |
| 2 |
| 17 |
x=136;
(2)x÷
| 4 |
| 9 |
| 15 |
| 16 |
x÷
| 4 |
| 9 |
| 4 |
| 9 |
| 15 |
| 16 |
| 4 |
| 9 |
x=
| 5 |
| 12 |
(3)
| 2 |
| 3 |
| 1 |
| 4 |
| 2 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 4 |
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
x=4.5.
点评:等式的性质是解方程的依据,解方程时注意对齐等号.
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