题目内容
24×(
|
(2
| ||||||||||||||||||||
|
[31÷233+
|
分析:(1)先运用乘法分配律简算,再算除法;
(2)先把小括号里面的运算运用乘法分配律简算,再算括号外的除法;
(3)先算小括号里面的加法,再算括号外的除法,然后用运用乘法分配律简算;
(4)先算小括号里面的除法,再算小括号里面的加法,然后算中括号里面的除法和乘法,接着算括号外的乘法,最后算加法.
(2)先把小括号里面的运算运用乘法分配律简算,再算括号外的除法;
(3)先算小括号里面的加法,再算括号外的除法,然后用运用乘法分配律简算;
(4)先算小括号里面的除法,再算小括号里面的加法,然后算中括号里面的除法和乘法,接着算括号外的乘法,最后算加法.
解答:解:(1)24×(
+1
-
-
)÷
,
=(24×
+24×1
-24×
-24×
)÷
,
=(21+42-22-12)÷
,
=29÷
,
=30;
(2)(2
×9
+7
×9.625)÷96
,
=(2
+7
)×9.625÷96
,
=10×9.625÷96
,
=96.25÷96.25,
=1;
(3)
×[(
+
)÷
-
],
=
×[
×
-
],
=
×[
-
],
=
×
-
×
,
=
-
,
=
;
(4)[31÷233+
×(
÷
+
)]+
×2,
=[31÷233+
×(
+
)]+
×2,
=[31÷233+
×6]+
×2,
=[
+
]+
×2,
=
+
×2,
=
+
,
=
.
| 7 |
| 8 |
| 3 |
| 4 |
| 11 |
| 12 |
| 1 |
| 2 |
| 29 |
| 30 |
=(24×
| 7 |
| 8 |
| 3 |
| 4 |
| 11 |
| 12 |
| 1 |
| 2 |
| 29 |
| 30 |
=(21+42-22-12)÷
| 29 |
| 30 |
=29÷
| 29 |
| 30 |
=30;
(2)(2
| 2 |
| 2007 |
| 5 |
| 8 |
| 2005 |
| 2007 |
| 1 |
| 4 |
=(2
| 2 |
| 2007 |
| 2005 |
| 2007 |
| 1 |
| 4 |
=10×9.625÷96
| 1 |
| 4 |
=96.25÷96.25,
=1;
(3)
| 3 |
| 2 |
| 3 |
| 2 |
| 8 |
| 5 |
| 5 |
| 6 |
| 7 |
| 3 |
=
| 3 |
| 2 |
| 31 |
| 10 |
| 6 |
| 5 |
| 7 |
| 3 |
=
| 3 |
| 2 |
| 93 |
| 25 |
| 7 |
| 3 |
=
| 3 |
| 2 |
| 93 |
| 25 |
| 3 |
| 2 |
| 7 |
| 3 |
=
| 279 |
| 50 |
| 175 |
| 50 |
=
| 52 |
| 25 |
(4)[31÷233+
| 5 |
| 233 |
| 1 |
| 4 |
| 1 |
| 18 |
| 3 |
| 2 |
| 91 |
| 233 |
=[31÷233+
| 5 |
| 233 |
| 9 |
| 2 |
| 3 |
| 2 |
| 91 |
| 233 |
=[31÷233+
| 5 |
| 233 |
| 91 |
| 233 |
=[
| 31 |
| 233 |
| 30 |
| 233 |
| 91 |
| 233 |
=
| 61 |
| 233 |
| 91 |
| 233 |
=
| 61 |
| 233 |
| 182 |
| 233 |
=
| 243 |
| 233 |
点评:本题考查了较复杂的计算,计算时要注意分析式中数据,运用合适的简便方法计算.
练习册系列答案
相关题目