题目内容
根据规律填空:
=(1-
)×
;
=(
-
)×
;
= × ;
= × .
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 4 |
| 1 |
| 9×5 |
| 1 |
| 5 |
| 1 |
| 9 |
| 1 |
| 4 |
| 1 |
| 9×13 |
| 1 |
| a?(a+4) |
考点:分数的拆项
专题:计算问题(巧算速算)
分析:由前两个算式可得:分子都是1,分母是相差4的两个数的积,所以可拆为两个分数的差再乘
,即
=(
-
)×
;据此解答.
| 1 |
| 4 |
| 1 |
| n(n+4) |
| 1 |
| n |
| 1 |
| n+4 |
| 1 |
| 4 |
解答:
解:
=(1-
)×
;
=(
-
)×
;
=(
-
)×
;
=(
-
)×
;
故答案为:(
-
),
,(
-
),
.
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 4 |
| 1 |
| 9×5 |
| 1 |
| 5 |
| 1 |
| 9 |
| 1 |
| 4 |
| 1 |
| 9×13 |
| 1 |
| 9 |
| 1 |
| 13 |
| 1 |
| 4 |
| 1 |
| a?(a+4) |
| 1 |
| a |
| 1 |
| a+4 |
| 1 |
| 4 |
故答案为:(
| 1 |
| 9 |
| 1 |
| 13 |
| 1 |
| 4 |
| 1 |
| a |
| 1 |
| a+4 |
| 1 |
| 4 |
点评:解答此题关键是根据算式特点发现规律,并运用规律解决问题,记住
=(
-
)×
.
| 1 |
| n(n+4) |
| 1 |
| n |
| 1 |
| n+4 |
| 1 |
| 4 |
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