题目内容
用递等式计算
(1)37.46+14.13+5.343 (2)100-33.43-18.96
(3)14.75-51.78+63.66 (4)92.154+54.113-49.3.
(1)37.46+14.13+5.343 (2)100-33.43-18.96
(3)14.75-51.78+63.66 (4)92.154+54.113-49.3.
考点:小数四则混合运算
专题:运算顺序及法则
分析:根据四则混合运算的运算顺序计算即可.
解答:
解:(1)37.46+14.13+5.343
=51.59+5.343
=56.933
(2)100-33.43-18.96
=66.57-18.96
=47.61
(3)14.75-51.78+63.66
=14.75+63.66-51.78
=78.41-51.78
=26.63
(4)92.154+54.113-49.3
=146.267-49.3
=96.967
=51.59+5.343
=56.933
(2)100-33.43-18.96
=66.57-18.96
=47.61
(3)14.75-51.78+63.66
=14.75+63.66-51.78
=78.41-51.78
=26.63
(4)92.154+54.113-49.3
=146.267-49.3
=96.967
点评:主要考查学生小数四则混合运算的运算能力,注意计算时小数点要对齐.
练习册系列答案
相关题目
科技书的本数是故事书的
,这里把( )看作单位“1”.
| 2 |
| 5 |
| A、故事书的本数 |
| B、科技书的本数 |
| C、故事书、科技书的总本数 |