题目内容
解方程:
x+
|
x-(
|
|
分析:(1)根据等式的性质,两边同时减去
即可;
(2)先把左边计算出来得x-
=
,再根据等式的性质两边同时加上
即可;
(3)根据等式的性质,两边同时减去
即可.
| 5 |
| 9 |
(2)先把左边计算出来得x-
| 11 |
| 14 |
| 1 |
| 2 |
| 11 |
| 14 |
(3)根据等式的性质,两边同时减去
| 3 |
| 4 |
解答:解:(1)x+
=1,
x+
-
=1-
,
x=
,
(2)x-(
+
)=
,
x-
=
,
x-
+
=
+
,
x=
,
(3)
+x=
,
+x-
=
-
,
x=
.
| 5 |
| 9 |
x+
| 5 |
| 9 |
| 5 |
| 9 |
| 5 |
| 9 |
x=
| 4 |
| 9 |
(2)x-(
| 3 |
| 14 |
| 4 |
| 7 |
| 1 |
| 2 |
x-
| 11 |
| 14 |
| 1 |
| 2 |
x-
| 11 |
| 14 |
| 11 |
| 14 |
| 1 |
| 2 |
| 11 |
| 14 |
x=
| 9 |
| 7 |
(3)
| 3 |
| 4 |
| 7 |
| 8 |
| 3 |
| 4 |
| 3 |
| 4 |
| 7 |
| 8 |
| 3 |
| 4 |
x=
| 1 |
| 8 |
点评:此题考查了等式的性质的灵活应用.
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