题目内容
若
=
成立,则x=( )
| 1 | ||||||
2+
|
| 12 |
| 29 |
| A、1 | B、2 | C、3 |
分析:采取从上向下,逐个去掉分子,2+
的值是
的倒数
;减去2,得到
,再取倒数得2+
=
;减去2,得到
,再取倒数,得到2+
=
;减去2,得到
,再取倒数,即可得解.
| 1 | ||||
2+
|
| 12 |
| 29 |
| 29 |
| 12 |
| 5 |
| 12 |
| 1 | ||
2+
|
| 12 |
| 5 |
| 2 |
| 5 |
| 1 |
| x |
| 5 |
| 2 |
| 1 |
| 2 |
解答:解:
=
,
2+
=
,
=
,
2+
=
,
=
,
2+
=
,
=
,
x=2;
故选:B.
| 1 | ||||||
2+
|
| 12 |
| 29 |
2+
| 1 | ||||
2+
|
| 29 |
| 12 |
| 1 | ||||
2+
|
| 5 |
| 12 |
2+
| 1 | ||
2+
|
| 12 |
| 5 |
| 1 | ||
2 +
|
| 2 |
| 5 |
2+
| 1 |
| x |
| 5 |
| 2 |
| 1 |
| x |
| 1 |
| 2 |
x=2;
故选:B.
点评:此题考查了连分数解方程,认真对待,逐步解决,是解决此题的关键.
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