题目内容
解方程.
|
(x-
|
x-
|
分析:(1)原式变为
+x=
,根据等式的性质,两边同减去
即可;
(2)根据等式的性质,两边同乘2得x-
=3,再同加上
即可;
(3)原式变为x-
=
,根据等式的性质,两边同加上
即可.
| 3 |
| 4 |
| 7 |
| 8 |
| 3 |
| 4 |
(2)根据等式的性质,两边同乘2得x-
| 4 |
| 7 |
| 4 |
| 7 |
(3)原式变为x-
| 2 |
| 9 |
| 7 |
| 6 |
| 2 |
| 9 |
解答:解:(1)
+
+x=
,
+x=
,
+x-
=
-
,
x=
;
(2)(x-
)÷2=1.5,
(x-
)÷2×2=1.5×2,
x-
=3,
x-
+
=3+
,
x=3
;
(3)x-
=
+
,
x-
=
,
x-
+
=
+
,
x=
.
| 5 |
| 12 |
| 1 |
| 3 |
| 7 |
| 8 |
| 3 |
| 4 |
| 7 |
| 8 |
| 3 |
| 4 |
| 3 |
| 4 |
| 7 |
| 8 |
| 3 |
| 4 |
x=
| 1 |
| 8 |
(2)(x-
| 4 |
| 7 |
(x-
| 4 |
| 7 |
x-
| 4 |
| 7 |
x-
| 4 |
| 7 |
| 4 |
| 7 |
| 4 |
| 7 |
x=3
| 4 |
| 7 |
(3)x-
| 2 |
| 9 |
| 2 |
| 3 |
| 1 |
| 2 |
x-
| 2 |
| 9 |
| 7 |
| 6 |
x-
| 2 |
| 9 |
| 2 |
| 9 |
| 7 |
| 6 |
| 2 |
| 9 |
x=
| 25 |
| 18 |
点评:在解方程时应根据等式的性质,即等式两边同加上、同减去、同乘上或同除以某一个数(0除外),等式的两边仍相等,同时注意“=”上下要对齐.
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