题目内容
| 2005+2004×2006 | 2005×2005+2006×2006-3 |
分析:原式=
=
=
=
=
,据此解答即可.
| 2005+2004×(2005+1) |
| 20052+(2005+1)2-3 |
| 2005+2004×2005+2004 |
| 20052+20052+2×2005+1-3 |
| 2005×(2004+1)+2004 |
| 20052+20052+2004×2 |
| 20052+2004 |
| 2×(20052+2004) |
| 1 |
| 2 |
解答:解:
,
=
,
=
,
=
,
=
,
=
.
| 2005+2004×2006 |
| 2005×2005+2006×2006-3 |
=
| 2005+2004×(2005+1) |
| 20052+(2005+1)2-3 |
=
| 2005+2004×2005+2004 |
| 20052+20052+2×2005+1-3 |
=
| 2005×(2004+1)+2004 |
| 20052+20052+2004×2 |
=
| 20052+2004 |
| 2×(20052+2004) |
=
| 1 |
| 2 |
点评:解答此题要找出题中的规律,灵活运用运算定律进行简算.
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