题目内容
[10
+(3
-1
)×1
]÷3
= .
| 2 |
| 3 |
| 2 |
| 7 |
| 1 |
| 2 |
| 3 |
| 25 |
| 1 |
| 3 |
考点:分数的四则混合运算
专题:运算顺序及法则
分析:首先把带分数都先化成假分数,利用除法的计算法则把除法变成乘法,能加减的先计算出来,去小括号时用乘法分配律.
解答:
解:[10
+(3
-1
)×1
]÷3
=[
+
×
-
×
]×
=[
+
-
]×
=[
+2]×
=
×
=
| 2 |
| 3 |
| 2 |
| 7 |
| 1 |
| 2 |
| 3 |
| 25 |
| 1 |
| 3 |
=[
| 32 |
| 3 |
| 23 |
| 7 |
| 28 |
| 25 |
| 3 |
| 2 |
| 28 |
| 25 |
| 3 |
| 10 |
=[
| 32 |
| 3 |
| 92 |
| 25 |
| 42 |
| 25 |
| 3 |
| 10 |
=[
| 32 |
| 3 |
| 3 |
| 10 |
=
| 38 |
| 3 |
| 3 |
| 10 |
=
| 19 |
| 5 |
点评:本题考查了分数四则混合运题目及其进行简算的能力.
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