题目内容
巧算.
+
+
+
+
+
+
+
(1+
+
)×(
+
+
+
)-(1+
+
+
+
)×(
+
)
| 1 |
| 2 |
| 1 |
| 6 |
| 1 |
| 8 |
| 1 |
| 12 |
| 1 |
| 20 |
| 1 |
| 30 |
| 1 |
| 42 |
| 1 |
| 56 |
(1+
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
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| 1 |
| 4 |
考点:分数的巧算
专题:计算问题(巧算速算)
分析:(1)首先把
分成1-
,把
分成
-
,…,然后再计算即可;
(2)首先把(1+
+
)×(
+
+
+
)变成(
+
+
+
)+(
+
)×(
+
+
+
),(1+
+
+
+
)×(
+
)变成(
+
)+(
+
+
+
)×(
+
),展开即可.
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 6 |
| 1 |
| 2 |
| 1 |
| 3 |
(2)首先把(1+
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 3 |
| 1 |
| 4 |
解答:
解:根据分析,可得
(1)
+
+
+
+
+
+
+
=1-
+
-
+
-
+
-
+
-
+
-
+
-
+
=1-
+
=1
(2)(1+
+
)×(
+
+
+
)-(1+
+
+
+
)×(
+
)
=(
+
+
+
)+(
+
)×(
+
+
+
)-[(
+
)+(
+
+
+
)×(
+
)]
=(
+
+
+
)+(
+
)×(
+
+
+
)-(
+
)-(
+
+
+
)×(
+
)
=(
+
+
+
)-(
+
)
=
+
=
(1)
| 1 |
| 2 |
| 1 |
| 6 |
| 1 |
| 8 |
| 1 |
| 12 |
| 1 |
| 20 |
| 1 |
| 30 |
| 1 |
| 42 |
| 1 |
| 56 |
=1-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 6 |
| 1 |
| 6 |
| 1 |
| 7 |
| 1 |
| 7 |
| 1 |
| 8 |
| 1 |
| 8 |
=1-
| 1 |
| 8 |
| 1 |
| 8 |
=1
(2)(1+
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
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| 1 |
| 5 |
| 1 |
| 3 |
| 1 |
| 4 |
=(
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| 1 |
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| 1 |
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| 1 |
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| 1 |
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| 1 |
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| 5 |
| 1 |
| 3 |
| 1 |
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=(
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| 1 |
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| 1 |
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| 5 |
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=(
| 1 |
| 2 |
| 1 |
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| 1 |
| 5 |
| 1 |
| 3 |
| 1 |
| 4 |
=
| 1 |
| 2 |
| 1 |
| 5 |
=
| 7 |
| 10 |
点评:此题主要考查了分数的巧算问题,解答此题的关键是灵活变形以及平方差公式的应用.
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