题目内容
| 解方程. x÷
|
90-
|
|
|
考点:方程的解和解方程
专题:简易方程
分析:(1)根据等式的性质,两边同时乘
即可;
(2)根据等式的性质,两边同时加
x,减60,然后同时乘
即可;
(3)先计算
x+
x=
x,然后等式的两边同时乘2即可;
(4)等式的两边同时减去
,然后等式的两边同时乘
即可.
| 8 |
| 5 |
(2)根据等式的性质,两边同时加
| 3 |
| 10 |
| 10 |
| 3 |
(3)先计算
| 3 |
| 10 |
| 1 |
| 5 |
| 1 |
| 2 |
(4)等式的两边同时减去
| 1 |
| 5 |
| 10 |
| 3 |
解答:
解:(1)x÷
=
×
x÷
×
=
×
×
x=
(2)90-
x=60
90-
x+
x-60=60+
x-60
x×
=30×
x=100
(3)
x+
x=
x=
x×2=
×2
x=1
(4)
x+
=
x+
-
=
-
x×
=
×
x=1.
| 8 |
| 5 |
| 5 |
| 8 |
| 2 |
| 5 |
x÷
| 8 |
| 5 |
| 8 |
| 5 |
| 5 |
| 8 |
| 2 |
| 5 |
| 8 |
| 5 |
x=
| 2 |
| 5 |
(2)90-
| 3 |
| 10 |
90-
| 3 |
| 10 |
| 3 |
| 10 |
| 3 |
| 10 |
| 3 |
| 10 |
| 10 |
| 3 |
| 10 |
| 3 |
x=100
(3)
| 3 |
| 10 |
| 1 |
| 5 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
x=1
(4)
| 3 |
| 10 |
| 1 |
| 5 |
| 1 |
| 2 |
| 3 |
| 10 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 2 |
| 1 |
| 5 |
| 3 |
| 10 |
| 10 |
| 3 |
| 3 |
| 10 |
| 10 |
| 3 |
x=1.
点评:本题考查了学生根据等式的性质解方程的能力,注意:①能化简先化简,②等号要对齐.
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