题目内容
| 简便运算,写出计算过程. ①25×0.32×1.25 |
②0.37×79+3.7×2.1 | ③2011÷2011
| ||||||||||||
④
|
⑤(
|
⑥1000+999×999. |
分析:①先把0.32分解成0.4×0.8,再运用乘法结合律简算;
②先根据积不变规律把0.37×79变成3.7×7.9,再运用乘法分配律简算;
③先把带分数化成假分数,转化过程运用乘法分配律,再根据除以一个数等于乘这个数的倒数计算除法,最后算加法;
④
=1-
,
=
-
…由此化简求解;
⑤运用乘法分配律简算;
⑥先把其中一个999分解成1000-1,再运用乘法分配律简算.
②先根据积不变规律把0.37×79变成3.7×7.9,再运用乘法分配律简算;
③先把带分数化成假分数,转化过程运用乘法分配律,再根据除以一个数等于乘这个数的倒数计算除法,最后算加法;
④
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 6 |
| 1 |
| 2 |
| 1 |
| 3 |
⑤运用乘法分配律简算;
⑥先把其中一个999分解成1000-1,再运用乘法分配律简算.
解答:解:①25×0.32×1.25,
=25×0.4×0.8×1.25,
=(25×0.4)×(0.8×1.25),
=10×1,
=10;
②0.37×79+3.7×2.1,
=3.7×7.9+3.7×2.1,
=3.7×(7.9+2.1),
=3.7×10,
=37;
③2011÷2011
+
,
=2011÷
+
,
=2011×
+
,
=2001×
,
=
+
,
=1;
④
+
+
+
+
,
=1-
+
-
+
-
+
-
+
-
,
=1-
,
=
;
⑤(
-
)×12,
=
×12-
×12,
=7-6,
=1;
⑥1000+999×999,
=1000+999×(1000-1),
=1000+999×1000-999×1,
=1000+999000-999,
=1000000-999,
=999001.
=25×0.4×0.8×1.25,
=(25×0.4)×(0.8×1.25),
=10×1,
=10;
②0.37×79+3.7×2.1,
=3.7×7.9+3.7×2.1,
=3.7×(7.9+2.1),
=3.7×10,
=37;
③2011÷2011
| 2011 |
| 2012 |
| 1 |
| 2013 |
=2011÷
| 2011×2012+2011 |
| 2012 |
| 1 |
| 2013 |
=2011×
| 2012 |
| 2011×(2012+1) |
| 1 |
| 2013 |
=2001×
| 2012 |
| 2011×2013 |
=
| 2012 |
| 2013 |
| 1 |
| 2013 |
=1;
④
| 1 |
| 2 |
| 1 |
| 6 |
| 1 |
| 12 |
| 1 |
| 20 |
| 1 |
| 30 |
=1-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 6 |
=1-
| 1 |
| 6 |
=
| 5 |
| 6 |
⑤(
| 7 |
| 12 |
| 1 |
| 2 |
=
| 7 |
| 12 |
| 1 |
| 2 |
=7-6,
=1;
⑥1000+999×999,
=1000+999×(1000-1),
=1000+999×1000-999×1,
=1000+999000-999,
=1000000-999,
=999001.
点评:本题考查了稍复杂的简便运算,注意分析式中数据,运用合适的简便方法计算.
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| ①25×0.32×1.25 | ②0.37×79+3.7×2.1 | ③2011÷2011 |
| ④ | ⑤( | ⑥1000+999×999. |