题目内容
比40m多25%是 m,比
m多25%是 m,比1m多
是 m.
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考点:百分数的加减乘除运算
专题:文字叙述题
分析:(1)把40m看作单位“1”,要求的数是40m的(1+25%),用乘法计算得解;
(2)把
m看成单位“1”,要求的数是
m的(1+25%),用乘法计算得解;
(3)把1m看作单位“1”,要求的数是1m的(1+
),用乘法计算得解.
(2)把
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(3)把1m看作单位“1”,要求的数是1m的(1+
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解答:
解:(1)40×(1+25%)
=40×1.25
=50(m).
答:比40m多25%是50m.
(2)
×(1+25%)
=
×
=
(m).
答:比
m多25%是
m.
(3)1×(1+
)
=1×
=
(m).
答:比1m多
是
m.
故答案为:50,
,
.
=40×1.25
=50(m).
答:比40m多25%是50m.
(2)
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=
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=
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答:比
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(3)1×(1+
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=1×
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=
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答:比1m多
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故答案为:50,
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点评:解答此题的关键是把问题转化成是求单位“1”的百分之几或几分之几是多少,进而用乘法计算得解.
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