题目内容
简便计算:1-
-
-
-
.
| 1 |
| 8 |
| 1 |
| 16 |
| 1 |
| 32 |
| 1 |
| 64 |
考点:分数的巧算
专题:计算问题(巧算速算)
分析:通过观察发现,算式中从第二项开始,前面的分数都是后面分数的2倍,于是原式变为1-
-(
-
+
-
+
-
),通过抵消,进行简算.
| 1 |
| 8 |
| 1 |
| 8 |
| 1 |
| 16 |
| 1 |
| 16 |
| 1 |
| 32 |
| 1 |
| 32 |
| 1 |
| 64 |
解答:
解:1-
-
-
-
=1-
-(
-
+
-
+
-
)
=
-(
-
)
=
+
=
| 1 |
| 8 |
| 1 |
| 16 |
| 1 |
| 32 |
| 1 |
| 64 |
=1-
| 1 |
| 8 |
| 1 |
| 8 |
| 1 |
| 16 |
| 1 |
| 16 |
| 1 |
| 32 |
| 1 |
| 32 |
| 1 |
| 64 |
=
| 7 |
| 8 |
| 1 |
| 8 |
| 1 |
| 64 |
=
| 3 |
| 4 |
| 1 |
| 64 |
=
| 49 |
| 64 |
点评:完成此题注意分数的拆分,通过加减相互抵消求得结果.
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