题目内容
解方程.
|
x÷
|
|
|
考点:方程的解和解方程
专题:简易方程
分析:(1)根据等式的性质,两边同乘上
即可;
(2)原方程可化简为x÷
=
,根据等式性质,两边同乘以
即可;
(3)根据等式性质,两边同乘以
得
x=3,两边再同乘以
即可;
(4)原方程可化简为
x=
,根据等式性质,两边再同乘以
即可.
| 21 |
| 8 |
(2)原方程可化简为x÷
| 6 |
| 35 |
| 10 |
| 9 |
| 6 |
| 35 |
(3)根据等式性质,两边同乘以
| 1 |
| 4 |
| 2 |
| 3 |
| 3 |
| 2 |
(4)原方程可化简为
| 11 |
| 15 |
| 22 |
| 5 |
| 15 |
| 11 |
解答:
解:(1)
x=
x×
=
×
x=
;
(2)x÷
=
÷
x÷
=
x÷
×
=
×
x=
;
(3)
x÷
=12
x÷
×
=12×
x=3
x×
=3×
x=
;
(4)
x+
x=
x=
x×
=
×
x=6.
| 8 |
| 21 |
| 4 |
| 15 |
| 8 |
| 21 |
| 21 |
| 8 |
| 4 |
| 15 |
| 21 |
| 8 |
x=
| 7 |
| 10 |
(2)x÷
| 6 |
| 35 |
| 26 |
| 45 |
| 13 |
| 25 |
x÷
| 6 |
| 35 |
| 10 |
| 9 |
x÷
| 6 |
| 35 |
| 6 |
| 35 |
| 10 |
| 9 |
| 6 |
| 35 |
x=
| 4 |
| 21 |
(3)
| 2 |
| 3 |
| 1 |
| 4 |
| 2 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 4 |
| 2 |
| 3 |
| 2 |
| 3 |
| 3 |
| 2 |
| 3 |
| 2 |
x=
| 9 |
| 2 |
(4)
| 2 |
| 5 |
| 1 |
| 3 |
| 22 |
| 5 |
| 11 |
| 15 |
| 22 |
| 5 |
| 11 |
| 15 |
| 15 |
| 11 |
| 22 |
| 5 |
| 15 |
| 11 |
x=6.
点评:此题考查了根据等式的性质解方程,即等式两边同加上、同减去、同乘上或同除以一个不为0的数,等式仍相等.同时注意“=”上下要对齐.
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