题目内容
用递等式计算
(1)1-(
+
)÷
(2)24×7.5+253÷23
(3)8÷[(4.3-3.5)×5].
(1)1-(
| 1 |
| 6 |
| 2 |
| 3 |
| 2 |
| 3 |
(2)24×7.5+253÷23
(3)8÷[(4.3-3.5)×5].
(1)1-(
+
)÷
=1-(
+
)×
,
=1-
×
,
=1-
,
=-
;
(2)24×7.5+253÷23
=180+11,
=191;
(3)8÷[(4.3-3.5)×5]
=8÷[0.8×5],
=8÷4,
=2.
| 1 |
| 6 |
| 2 |
| 3 |
| 2 |
| 3 |
=1-(
| 1 |
| 6 |
| 4 |
| 6 |
| 3 |
| 2 |
=1-
| 5 |
| 6 |
| 3 |
| 2 |
=1-
| 5 |
| 4 |
=-
| 1 |
| 4 |
(2)24×7.5+253÷23
=180+11,
=191;
(3)8÷[(4.3-3.5)×5]
=8÷[0.8×5],
=8÷4,
=2.
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