题目内容

(1)
5
7
-0.72+(
2
7
-0.28)
(2)
9
20
÷[
1
2
×(
2
5
+
4
5
)]
(3)解方程:(x+7)×
1
12
=1.
(1)
5
7
+0.72+
2
7
+0.28,
=(
5
7
+
2
7
)+(0.72+0.28),
=1+1,
=2;

(2)
9
20
÷[
1
2
×(
2
5
+
4
5
)],
=
9
20
÷(
1
2
×
2
5
+
1
2
×
4
5
),
=
9
20
÷(
1
5
+
2
5
),
=
9
20
÷
3
5

=
9
20
×
5
3

=
3
4


(3)(x+7)×
1
12
=1,
(x+7)×
1
12
×12=1×12,
x+7=12,
x+7-7=12-7,
x=5.
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