题目内容
(1)
| (2)
| (3)解方程:(x+7)×
|
(1)
+0.72+
+0.28,
=(
+
)+(0.72+0.28),
=1+1,
=2;
(2)
÷[
×(
+
)],
=
÷(
×
+
×
),
=
÷(
+
),
=
÷
,
=
×
,
=
;
(3)(x+7)×
=1,
(x+7)×
×12=1×12,
x+7=12,
x+7-7=12-7,
x=5.
| 5 |
| 7 |
| 2 |
| 7 |
=(
| 5 |
| 7 |
| 2 |
| 7 |
=1+1,
=2;
(2)
| 9 |
| 20 |
| 1 |
| 2 |
| 2 |
| 5 |
| 4 |
| 5 |
=
| 9 |
| 20 |
| 1 |
| 2 |
| 2 |
| 5 |
| 1 |
| 2 |
| 4 |
| 5 |
=
| 9 |
| 20 |
| 1 |
| 5 |
| 2 |
| 5 |
=
| 9 |
| 20 |
| 3 |
| 5 |
=
| 9 |
| 20 |
| 5 |
| 3 |
=
| 3 |
| 4 |
(3)(x+7)×
| 1 |
| 12 |
(x+7)×
| 1 |
| 12 |
x+7=12,
x+7-7=12-7,
x=5.
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