题目内容
| 解方程 x÷
|
|
分析:(1)原式变为
x=
×
,再根据等式的性质,两边同乘
即可;
(2)根据等式的性质,两边同乘
,再同乘
即可.
| 35 |
| 6 |
| 26 |
| 45 |
| 25 |
| 13 |
| 6 |
| 35 |
(2)根据等式的性质,两边同乘
| 1 |
| 4 |
| 3 |
| 2 |
解答:解:(1)x÷
=
÷
,
x=
×
,
x=
,
x×
=
×
,
x=
;
(2)
x÷
=12,
x÷
×
=12×
,
x=3,
x×
=3×
,
x=
.
| 6 |
| 35 |
| 26 |
| 45 |
| 13 |
| 25 |
| 35 |
| 6 |
| 26 |
| 45 |
| 25 |
| 13 |
| 35 |
| 6 |
| 10 |
| 9 |
| 35 |
| 6 |
| 6 |
| 35 |
| 10 |
| 9 |
| 6 |
| 35 |
x=
| 4 |
| 21 |
(2)
| 2 |
| 3 |
| 1 |
| 4 |
| 2 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 4 |
| 2 |
| 3 |
| 2 |
| 3 |
| 3 |
| 2 |
| 3 |
| 2 |
x=
| 9 |
| 2 |
点评:在解方程时应根据等式的性质,即等式两边同加上、同减去、同乘上或同除以某一个数(0除外),等式的两边仍相等,同时注意“=”上下要对齐.
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