题目内容
计算:(3
+5
+7
+4)÷(
+2
+3
+4
).
| 1 |
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| 4 |
| 3 |
| 5 |
| 2 |
| 3 |
| 3 |
| 4 |
| 4 |
| 5 |
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| 6 |
分析:首先把分数整数部分和分数部分化简,然后被除数和除数同时乘3、4、5、6的最小公倍数60,商不变,从而把复杂的分数计算,简化为整数的计算,即可得解.
解答:解:(3
+5
+7
+4)÷(
+2
+3
+4
)
=[(19+
+
+
)×60]÷[(1+3+4+5-
-
-
-
)×60]
=(19×60+
×60+
×60+
×60)÷(13×60-
×60-
×60-
×60-
×60)
=(1140+20+30+36)÷(780-20-15-12-10)
=1226÷723
=1
.
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| 5 |
| 2 |
| 3 |
| 3 |
| 4 |
| 4 |
| 5 |
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| 6 |
=[(19+
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| 3 |
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| 4 |
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| 5 |
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| 6 |
=(19×60+
| 1 |
| 3 |
| 1 |
| 2 |
| 3 |
| 5 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 6 |
=(1140+20+30+36)÷(780-20-15-12-10)
=1226÷723
=1
| 503 |
| 723 |
点评:此题考查了分数的巧算,利用被除数和除数同时乘所有分数分母的最小公倍数,商不变来解决问题.
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