题目内容
(1-
)(1-
)(1-
)…(1-
).
| 1 |
| 22 |
| 1 |
| 32 |
| 1 |
| 42 |
| 1 |
| 20042 |
考点:分数的巧算
专题:计算问题(巧算速算)
分析:首先把每一个因数化成两个分数乘积的形式,例如:1-
=(1-
)×(1+
)=
×
,1-
=(1-
)×(1+
)=
×
…然后解答即可.
| 1 |
| 22 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 3 |
| 2 |
| 1 |
| 32 |
| 1 |
| 3 |
| 1 |
| 3 |
| 2 |
| 3 |
| 4 |
| 3 |
解答:
解:(1-
)(1-
)(1-
)…(1-
)
=(1-
)(1+
)(1-
)(1+
)(1-
)(1+
)…(1-
)(1+
)
=
×
×
×
×
×
×…×
×
=
×
=
| 1 |
| 22 |
| 1 |
| 32 |
| 1 |
| 42 |
| 1 |
| 20042 |
=(1-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 2004 |
| 1 |
| 2004 |
=
| 1 |
| 2 |
| 3 |
| 2 |
| 2 |
| 3 |
| 4 |
| 3 |
| 3 |
| 4 |
| 5 |
| 4 |
| 2003 |
| 2004 |
| 2005 |
| 2004 |
=
| 1 |
| 2 |
| 2005 |
| 2004 |
=
| 2005 |
| 4008 |
点评:解答此题的关键是把每一个因数化成两个分数乘积的形式.
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