题目内容
|
|
分析:(1)根据加法的交换律和连减的简便方法计算即可;
(2)先将原式变形为
×
+
×
,再根据乘法分配律简便计算.
(2)先将原式变形为
| 2 |
| 9 |
| 4 |
| 13 |
| 4 |
| 13 |
| 7 |
| 9 |
解答:解:(1)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(2)
×
+
÷
,
=
×
+
×
,
=
×(
+
),
=
×1,
=
.
| 1 |
| 5 |
| 1 |
| 8 |
| 4 |
| 5 |
| 7 |
| 8 |
=(
| 1 |
| 5 |
| 4 |
| 5 |
| 1 |
| 8 |
| 7 |
| 8 |
=1+1,
=2;
(2)
| 2 |
| 9 |
| 4 |
| 13 |
| 4 |
| ?13 |
| 9 |
| 7 |
=
| 2 |
| 9 |
| 4 |
| 13 |
| 4 |
| 13 |
| 7 |
| 9 |
=
| 4 |
| 13 |
| 2 |
| 9 |
| 7 |
| 9 |
=
| 4 |
| 13 |
=
| 4 |
| 13 |
点评:注意运算顺序和运算法则,灵活运用所学的运算律简便计算.
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