题目内容
(1)15
÷14=
(2)8
-(
+6
)=
(3)31.4+15.19+20.6+32.81=
(4)9
-3
+2
-8
=
(5)44
-23
-23
+44
=
(6)(1
+2
+3
+1
)÷5=
(7)9+19+199+1999=
(8)0.9+0.99+0.999+0.111=
| 1 |
| 13 |
(2)8
| 6 |
| 7 |
| 23 |
| 45 |
| 6 |
| 7 |
(3)31.4+15.19+20.6+32.81=
(4)9
| 5 |
| 7 |
| 4 |
| 9 |
| 4 |
| 9 |
| 2 |
| 7 |
(5)44
| 1 |
| 3 |
| 1 |
| 5 |
| 1 |
| 5 |
| 2 |
| 3 |
(6)(1
| 3 |
| 4 |
| 2 |
| 3 |
| 1 |
| 4 |
| 1 |
| 3 |
(7)9+19+199+1999=
(8)0.9+0.99+0.999+0.111=
分析:(1)15
=14+1
,然后再根据乘法分配律进行简算;
(2)根据减法的性质进行简算;
(3)根据加法交换律和结合律进行简算;
(4)根据加法交换律和结合律进行简算;
(5)根据加法交换律和结合律进行简算;
(6)根据加法交换律和结合律进行简算;
(7)9=1+1+1+6,然后再根据加法交换律和结合律进行简算;
(8)0.111=0.1+0.01+0.001,然后再根据加法交换律和结合律进行简算.
| 1 |
| 13 |
| 1 |
| 13 |
(2)根据减法的性质进行简算;
(3)根据加法交换律和结合律进行简算;
(4)根据加法交换律和结合律进行简算;
(5)根据加法交换律和结合律进行简算;
(6)根据加法交换律和结合律进行简算;
(7)9=1+1+1+6,然后再根据加法交换律和结合律进行简算;
(8)0.111=0.1+0.01+0.001,然后再根据加法交换律和结合律进行简算.
解答:解:
(1)15
÷14,
=(14+1
)×
,
=14×
+1
×
,
=1+
,
=1
;
(2)8
-(
+6
),
=8
-
-6
,
=8
-6
-
,
=2-
,
=1
;
(3)31.4+15.19+20.6+32.81,
=(31.4+20.6)+(15.19+32.81),
=52+48,
=100;
(4)9
-3
+2
-8
,
=(9
-8
)-(3
-2
),
=1
-1,
=
;
(5)44
-23
-23
+44
,
=(44
+44
)-(23
+23
),
=89-46
,
=42
;
(6)(1
+2
+3
+1
)÷5,
=[(1
+3
)+(2
+1
)]÷5,
=[5+4]÷5,
=9÷5,
=1.8;
(7)9+19+199+1999,
=(1+1+1+6)+19+199+1999,
=(1+19)+(1+199)+(1+1999)+6,
=20+200+2000+6,
=2220+6,
=2226;
(8)0.9+0.99+0.999+0.111,
=0.9+0.99+0.999+(0.1+0.01+0.001),
=(0.9+0.1)+(0.99+0.01)+(0.999+0.001),
=1+1+1,
=3.
(1)15
| 1 |
| 13 |
=(14+1
| 1 |
| 13 |
| 1 |
| 14 |
=14×
| 1 |
| 14 |
| 1 |
| 13 |
| 1 |
| 14 |
=1+
| 1 |
| 13 |
=1
| 1 |
| 13 |
(2)8
| 6 |
| 7 |
| 23 |
| 45 |
| 6 |
| 7 |
=8
| 6 |
| 7 |
| 23 |
| 45 |
| 6 |
| 7 |
=8
| 6 |
| 7 |
| 6 |
| 7 |
| 23 |
| 45 |
=2-
| 23 |
| 45 |
=1
| 22 |
| 45 |
(3)31.4+15.19+20.6+32.81,
=(31.4+20.6)+(15.19+32.81),
=52+48,
=100;
(4)9
| 5 |
| 7 |
| 4 |
| 9 |
| 4 |
| 9 |
| 2 |
| 7 |
=(9
| 5 |
| 7 |
| 2 |
| 7 |
| 4 |
| 9 |
| 4 |
| 9 |
=1
| 3 |
| 7 |
=
| 3 |
| 7 |
(5)44
| 1 |
| 3 |
| 1 |
| 5 |
| 1 |
| 5 |
| 2 |
| 3 |
=(44
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 5 |
| 1 |
| 5 |
=89-46
| 2 |
| 5 |
=42
| 3 |
| 5 |
(6)(1
| 3 |
| 4 |
| 2 |
| 3 |
| 1 |
| 4 |
| 1 |
| 3 |
=[(1
| 3 |
| 4 |
| 1 |
| 4 |
| 2 |
| 3 |
| 1 |
| 3 |
=[5+4]÷5,
=9÷5,
=1.8;
(7)9+19+199+1999,
=(1+1+1+6)+19+199+1999,
=(1+19)+(1+199)+(1+1999)+6,
=20+200+2000+6,
=2220+6,
=2226;
(8)0.9+0.99+0.999+0.111,
=0.9+0.99+0.999+(0.1+0.01+0.001),
=(0.9+0.1)+(0.99+0.01)+(0.999+0.001),
=1+1+1,
=3.
点评:完成本题要注意分析式中数据,运用合适的简便方法计算.
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