题目内容
解方程.
x=15
x÷
=
x÷
=18.
| 5 |
| 8 |
x÷
| 2 |
| 9 |
| 6 |
| 7 |
| 3 |
| 4 |
| 1 |
| 6 |
分析:(1)根据等式性质,两边同除以
即可;
(2)根据等式性质,两边同乘
,计算得解;
(3)根据等式性质,两边同乘
,再同除以
即可.
| 5 |
| 8 |
(2)根据等式性质,两边同乘
| 2 |
| 9 |
(3)根据等式性质,两边同乘
| 1 |
| 6 |
| 3 |
| 4 |
解答:解:(1)
x=15,
x÷
=15÷
,
x=15×
,
x=24;
(2)x÷
=
,
x÷
×
=
×
,
x=
;
(3)
x÷
=18,
x÷
×
=18×
,
x=3,
x÷
=3÷
,
x=3×
,
x=4.
| 5 |
| 8 |
| 5 |
| 8 |
| 5 |
| 8 |
| 5 |
| 8 |
x=15×
| 8 |
| 5 |
x=24;
(2)x÷
| 2 |
| 9 |
| 6 |
| 7 |
x÷
| 2 |
| 9 |
| 2 |
| 9 |
| 6 |
| 7 |
| 2 |
| 9 |
x=
| 4 |
| 21 |
(3)
| 3 |
| 4 |
| 1 |
| 6 |
| 3 |
| 4 |
| 1 |
| 6 |
| 1 |
| 6 |
| 1 |
| 6 |
| 3 |
| 4 |
| 3 |
| 4 |
| 3 |
| 4 |
| 3 |
| 4 |
x=3×
| 4 |
| 3 |
x=4.
点评:解方程的依据就是等式的性质,即等式两边同时加上或减去,同时乘上或除以相同的数(0除外),等式的左右两边相等.
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