题目内容
计算,能简便的要简便
(1.5+
)÷
-
=
×3.7+0.6+5.3×60%=
9.81×0.1+0.5×98.1+0.049×981=
+
+…+
=
(1.5+
| 2 |
| 3 |
| 1 |
| 6 |
| 2 |
| 3 |
| 3 |
| 5 |
9.81×0.1+0.5×98.1+0.049×981=
| 1 |
| 1×2 |
| 1 |
| 2×3 |
| 1 |
| 99×100 |
考点:四则混合运算中的巧算,分数的拆项
专题:计算问题(巧算速算)
分析:(1)把小数化为分数,先算括号内的,再算括号外的除法,最后算减法;
(2)把分数和百分数换位小数,运用乘法分配律简算;
(3)通过数字变形,运用乘法分配律简算;
(4)把每个分数拆成两个分数相减的形式,然后通过加减相互抵消,求得结果.
(2)把分数和百分数换位小数,运用乘法分配律简算;
(3)通过数字变形,运用乘法分配律简算;
(4)把每个分数拆成两个分数相减的形式,然后通过加减相互抵消,求得结果.
解答:
解:(1)(1.5+
)÷
-
=(
+
)×6-
=
×6-
=13-
=12
;
(2)
×3.7+0.6+5.3×60%
=0.6×3.7+0.6+5.3×0.6
=0.6×(3.7+1+5.3)
=0.6×10
=6;
(3)9.81×0.1+0.5×98.1+0.049×981
=9.81×0.1+5×9.81+4.9×9.81
=9.81×(0.1+5+4.9)
=9.81×10
=98.1;
(4)
+
+…+
=1-
+
-
+…+
-
=1-
=
.
| 2 |
| 3 |
| 1 |
| 6 |
| 2 |
| 3 |
=(
| 3 |
| 2 |
| 2 |
| 3 |
| 2 |
| 3 |
=
| 13 |
| 6 |
| 2 |
| 3 |
=13-
| 2 |
| 3 |
=12
| 1 |
| 3 |
(2)
| 3 |
| 5 |
=0.6×3.7+0.6+5.3×0.6
=0.6×(3.7+1+5.3)
=0.6×10
=6;
(3)9.81×0.1+0.5×98.1+0.049×981
=9.81×0.1+5×9.81+4.9×9.81
=9.81×(0.1+5+4.9)
=9.81×10
=98.1;
(4)
| 1 |
| 1×2 |
| 1 |
| 2×3 |
| 1 |
| 99×100 |
=1-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 99 |
| 1 |
| 100 |
=1-
| 1 |
| 100 |
=
| 99 |
| 100 |
点评:要想算得快、算得巧,就要仔细观察题目中数字构成的特点和规律,运用运算定律或运算技巧,进行简便计算.
练习册系列答案
相关题目
一辆汽车3小时行了215( )
| A、米 | B、千米 | C、分米 | D、厘米 |