题目内容
脱式计算(能简算的一定要简算
÷(3-
-
)
88×125;
12×(
+
-
);
×
+
×
(
+
)×27;
÷[
-(
+
)].
| 1 |
| 4 |
| 5 |
| 13 |
| 8 |
| 13 |
88×125;
12×(
| 1 |
| 4 |
| 1 |
| 6 |
| 1 |
| 3 |
| 3 |
| 4 |
| 5 |
| 6 |
| 3 |
| 4 |
| 1 |
| 6 |
(
| 8 |
| 9 |
| 4 |
| 27 |
| 4 |
| 9 |
| 5 |
| 6 |
| 1 |
| 6 |
| 1 |
| 3 |
考点:整数、分数、小数、百分数四则混合运算,运算定律与简便运算
专题:运算顺序及法则,运算定律及简算
分析:(1)括号内根据减法的性质简算,最后算除法即可;
(2)首先把88分成8×11,然后根据乘法结合律简算即可;
(3)(4)(5)根据乘法分配律简算即可;
(6)首先计算小括号里面的,然后计算中括号里面的,最后计算中括号外面的即可.
(2)首先把88分成8×11,然后根据乘法结合律简算即可;
(3)(4)(5)根据乘法分配律简算即可;
(6)首先计算小括号里面的,然后计算中括号里面的,最后计算中括号外面的即可.
解答:
解:(1)
÷(3-
-
)
=
÷[3-(
+
)]
=
÷[3-1]
=
(2)88×125
=8×11×125
=(8×125)×11
=1000×11
=11000
(3)12×(
+
-
)
=12×
+12×
-12×
=3+2-4
=1
(4)
×
+
×
=
×(
+
)
=
×1
=
(5)(
+
)×27
=
×27+
×27
=24+4
=28
(6)
÷[
-(
+
)]
=
÷[
-
]
=
÷
=1
| 1 |
| 4 |
| 5 |
| 13 |
| 8 |
| 13 |
=
| 1 |
| 4 |
| 5 |
| 13 |
| 8 |
| 13 |
=
| 1 |
| 4 |
=
| 1 |
| 8 |
(2)88×125
=8×11×125
=(8×125)×11
=1000×11
=11000
(3)12×(
| 1 |
| 4 |
| 1 |
| 6 |
| 1 |
| 3 |
=12×
| 1 |
| 4 |
| 1 |
| 6 |
| 1 |
| 3 |
=3+2-4
=1
(4)
| 3 |
| 4 |
| 5 |
| 6 |
| 3 |
| 4 |
| 1 |
| 6 |
=
| 3 |
| 4 |
| 5 |
| 6 |
| 1 |
| 6 |
=
| 3 |
| 4 |
=
| 3 |
| 4 |
(5)(
| 8 |
| 9 |
| 4 |
| 27 |
=
| 8 |
| 9 |
| 4 |
| 27 |
=24+4
=28
(6)
| 4 |
| 9 |
| 5 |
| 6 |
| 1 |
| 6 |
| 1 |
| 3 |
=
| 4 |
| 9 |
| 5 |
| 6 |
| 3 |
| 6 |
=
| 4 |
| 9 |
| 1 |
| 3 |
=1
| 1 |
| 3 |
点评:此题主要考查了整数、分数四则混合运算,注意运算顺序,注意减法的性质、乘法运算定律的应用.
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