题目内容
| 解方程. x+
|
|
x-(
|
分析:(1)利用等式的性质两边同时减去
,即可解答;
(2)根据等式的性质,先把两边同时加上x得出
+x=
,再利用等式的性质两边同时减去
,即可解答;
(3)先算出
-
的得数
,根据等式的性质,两边同时加上
,即可解答.
| 7 |
| 17 |
(2)根据等式的性质,先把两边同时加上x得出
| 3 |
| 8 |
| 2 |
| 5 |
| 3 |
| 8 |
(3)先算出
| 7 |
| 9 |
| 5 |
| 18 |
| 1 |
| 2 |
| 1 |
| 2 |
解答:解:(1)x+
=
,
x+
-
=
-
,
x=0;
(2)
-x=
,
-x+x=
+x,
+x=
,
+x-
=
-
,
x=
;
(3)x-(
-
)=
,
x-
=
,
x-
+
=
+
,
x=
.
| 7 |
| 17 |
| 21 |
| 51 |
x+
| 7 |
| 17 |
| 7 |
| 17 |
| 21 |
| 51 |
| 7 |
| 17 |
x=0;
(2)
| 2 |
| 5 |
| 3 |
| 8 |
| 2 |
| 5 |
| 3 |
| 8 |
| 3 |
| 8 |
| 2 |
| 5 |
| 3 |
| 8 |
| 3 |
| 8 |
| 2 |
| 5 |
| 3 |
| 8 |
x=
| 1 |
| 40 |
(3)x-(
| 7 |
| 9 |
| 5 |
| 18 |
| 2 |
| 9 |
x-
| 1 |
| 2 |
| 2 |
| 9 |
x-
| 1 |
| 2 |
| 1 |
| 2 |
| 2 |
| 9 |
| 1 |
| 2 |
x=
| 13 |
| 18 |
点评:此题考查了利用等式的性质解方程的方法的灵活应用.
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