题目内容
| 3 |
| 4 |
| 2 |
| 3 |
| 2 |
| 3 |
| 7 |
| 8 |
| 7 |
| 8 |
| 4 |
| 7 |
| 5 |
| 6 |
| 3 |
| 5 |
| 3 |
| 5 |
| 1 |
| 2 |
| 1 |
| 2 |
分析:分析题意可知,假设出任何一个空的答案,就可根据等式算出其他空的答案.
解答:解:假设第一个空的答案为
,
则第二个空的答案是:
×
=
,
÷
=
×
=
;
则第二个空的答案是:
×
=
,
÷
=
×
=
;
则第四个空的答案是
×
=
,1-
=
;
故答案为:
,
,
,
| 2 |
| 3 |
则第二个空的答案是:
| 3 |
| 4 |
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 4 |
| 7 |
| 1 |
| 2 |
| 7 |
| 4 |
| 7 |
| 8 |
则第二个空的答案是:
| 3 |
| 4 |
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 5 |
| 6 |
| 1 |
| 2 |
| 6 |
| 5 |
| 3 |
| 5 |
则第四个空的答案是
| 3 |
| 4 |
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
故答案为:
| 2 |
| 3 |
| 7 |
| 8 |
| 3 |
| 5 |
| 1 |
| 2 |
点评:如果题目求不出答案,可假设一个答案是已知的,根据已知条件再求其他答案.
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