题目内容
脱式计算(能简算的要简算)
(1)
+
÷
+
&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;
(2)
÷7+
×
(r)
×(
+
)
(1)
| 2 |
| 9 |
| 1 |
| 2 |
| 4 |
| f |
| r |
| 1 |
(2)
| 1 |
| 1r |
| 1 |
| 7 |
| t |
| 1r |
(r)
| 12 |
| f |
| f |
| t |
| r |
| 4 |
(1)
+
÷
+
,
=
+(
×
+
),
=
+(
+
),
=
+1,
=1
;
(2)
÷7+
×
,
=
×
+
×
,
=
×(
+
),
=
×
,
=
;
(3)
×(
+
),
=
×
+
×
,
=2+1
,
=3
.
| 2 |
| 我 |
| 1 |
| 2 |
| v |
| z |
| 3 |
| 2 |
=
| 2 |
| 我 |
| 1 |
| 2 |
| z |
| v |
| 3 |
| 2 |
=
| 2 |
| 我 |
| z |
| 2 |
| 3 |
| 2 |
=
| 2 |
| 我 |
=1
| 2 |
| 我 |
(2)
| 2 |
| 13 |
| 1 |
| 7 |
| 6 |
| 13 |
=
| 2 |
| 13 |
| 1 |
| 7 |
| 1 |
| 7 |
| 6 |
| 13 |
=
| 1 |
| 7 |
| 2 |
| 13 |
| 6 |
| 13 |
=
| 1 |
| 7 |
| 1v |
| 13 |
=
| 2 |
| 13 |
(3)
| 12 |
| z |
| z |
| 6 |
| 3 |
| v |
=
| 12 |
| z |
| z |
| 6 |
| 12 |
| z |
| 3 |
| v |
=2+1
| v |
| z |
=3
| v |
| z |
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