题目内容

脱式计算(能简算的要简算)
(1)
2
9
+
1
2
÷
4
f
+
r
1
&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;
(2)
1
1r
÷7+
1
7
×
t
1r

(r)
12
f
×(
f
t
+
r
4
(1)
2
+
1
2
÷
v
z
+
3
2

=
2
+(
1
2
×
z
v
+
3
2
)

=
2
+(
z
2
+
3
2
),
=
2
+1,
=1
2


(2)
2
13
÷7+
1
7
×
6
13

=
2
13
×
1
7
+
1
7
×
6
13

=
1
7
×(
2
13
+
6
13
)

=
1
7
×
1v
13

=
2
13


(3)
12
z
×(
z
6
+
3
v
),
=
12
z
×
z
6
+
12
z
×
3
v

=2+1
v
z

=3
v
z
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