题目内容
9×(
|
|
(
|
|
分析:(1)按运算顺序计算,先算括号内的,再算括号外的;
(2)把除法改为乘法,发现前后两项相等,用其中一项乘2即可;
(3)按运算顺序计算,先算括号内的,再算括号外的;
(4)按运算顺序计算,先算小括号内的,再算中括号内的,最后算括号外的.
(2)把除法改为乘法,发现前后两项相等,用其中一项乘2即可;
(3)按运算顺序计算,先算括号内的,再算括号外的;
(4)按运算顺序计算,先算小括号内的,再算中括号内的,最后算括号外的.
解答:解:(1)9×(
-
)÷
,
=9×(
-
)÷
,
=9×
×
,
=4;
(2)
÷
+
×
,
=
×
+
×
,
=
×
×2,
=
;
(3)(
+
)÷
-
,
=(
+
)×
-
,
=
×
-
,
=
-
,
=
;
(4)
×[
-(
-
)],
=
×[
-(
-
)],
=
×[
-
],
=
×
,
=
.
| 2 |
| 3 |
| 2 |
| 5 |
| 3 |
| 5 |
=9×(
| 10 |
| 15 |
| 6 |
| 15 |
| 3 |
| 5 |
=9×
| 4 |
| 15 |
| 5 |
| 3 |
=4;
(2)
| 3 |
| 17 |
| 3 |
| 4 |
| 3 |
| 17 |
| 4 |
| 3 |
=
| 3 |
| 17 |
| 4 |
| 3 |
| 3 |
| 17 |
| 4 |
| 3 |
=
| 3 |
| 17 |
| 4 |
| 3 |
=
| 8 |
| 17 |
(3)(
| 1 |
| 2 |
| 2 |
| 3 |
| 3 |
| 4 |
| 2 |
| 3 |
=(
| 3 |
| 6 |
| 4 |
| 6 |
| 4 |
| 3 |
| 2 |
| 3 |
=
| 7 |
| 6 |
| 4 |
| 3 |
| 2 |
| 3 |
=
| 14 |
| 9 |
| 6 |
| 9 |
=
| 8 |
| 9 |
(4)
| 8 |
| 9 |
| 3 |
| 4 |
| 7 |
| 16 |
| 1 |
| 4 |
=
| 8 |
| 9 |
| 3 |
| 4 |
| 7 |
| 16 |
| 4 |
| 16 |
=
| 8 |
| 9 |
| 12 |
| 16 |
| 3 |
| 16 |
=
| 8 |
| 9 |
| 9 |
| 16 |
=
| 1 |
| 2 |
点评:此题主要考查学生对四则混合运算顺序的掌握情况.
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