题目内容
某工厂的女工的占
,又招进50名男工,这时女工占总人数的
,工厂原有多少工人?
| 3 |
| 4 |
| 2 |
| 3 |
分析:原来工厂的女工的占
,则男工占1-
=
,则男工人数是女工人数的
÷
=
,招进50名男工后,男工占女工人数的(1-
)÷
=
,则这50人占女工人数的
-
=
,则女工有50÷
=300人,所以工厂原有300÷
=400人.
| 3 |
| 4 |
| 3 |
| 4 |
| 1 |
| 4 |
| 1 |
| 4 |
| 3 |
| 4 |
| 1 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 6 |
| 1 |
| 6 |
| 3 |
| 4 |
解答:解:50÷[(1-
)÷
-(1-
)÷
]÷
=50÷[
÷
-
÷
]÷
,
=50÷[
-
]×
,
=50×6×
,
=400(人);
答:工厂原有400名工人.
| 2 |
| 3 |
| 2 |
| 3 |
| 3 |
| 4 |
| 3 |
| 4 |
| 3 |
| 4 |
=50÷[
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 4 |
| 3 |
| 4 |
| 3 |
| 4 |
=50÷[
| 1 |
| 2 |
| 1 |
| 3 |
| 4 |
| 3 |
=50×6×
| 4 |
| 3 |
=400(人);
答:工厂原有400名工人.
点评:明确这一过程中女工人数没有发生变化,并由此根据前后男工占女工人数人分率的变化求出女工有多少是完成本题的关键.
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