题目内容
脱式计算,能简算的要简算.
(1)5.12×
|
(2)1999+999×999 | ||||||||||||||||
(3)48-(32÷
|
(4)11×11×11-11×11 | ||||||||||||||||
(5)
|
(6)
|
考点:分数的简便计算,运算定律与简便运算,小数四则混合运算
专题:运算顺序及法则
分析:(1)根据乘法分配律进行简算;
(2)根据乘法分配律进行简算;
(3)先算除法,再根据减法的性质进行简算;
(4)根据乘法分配律进行简算;
(5)根据减法的性质进行简算;
(6)根据分数的拆项进行简算.
(2)根据乘法分配律进行简算;
(3)先算除法,再根据减法的性质进行简算;
(4)根据乘法分配律进行简算;
(5)根据减法的性质进行简算;
(6)根据分数的拆项进行简算.
解答:
解:(1)5.12×
+2.875÷4
=5.12×
+2.875×
=(5.12+2.875)×
=7.995×
=1.99875;
(2)1999+999×999
=1000+999+999×999
=1000+(999+1)×999
=1000+1000×999
=1000×(1+999)
=1000×1000
=1000000;
(3)48-(32÷
-
)
=48-(12-
)
=48-12+
=36+
=38
;
(4)11×11×11-11×11
=11×11×(11-1)
=11×11×10
=121×10
=1210;
(5)
-
-
=
-(
+
)
=
-
=
;
(6)
+
+
+
+
=(1-
)+(
-
)+(
-
)+(
-
)+(
-
)
=1-
+
-
+
-
+
-
+
-
=1-
=
.
| 1 |
| 4 |
=5.12×
| 1 |
| 4 |
| 1 |
| 4 |
=(5.12+2.875)×
| 1 |
| 4 |
=7.995×
| 1 |
| 4 |
=1.99875;
(2)1999+999×999
=1000+999+999×999
=1000+(999+1)×999
=1000+1000×999
=1000×(1+999)
=1000×1000
=1000000;
(3)48-(32÷
| 8 |
| 3 |
| 12 |
| 5 |
=48-(12-
| 12 |
| 5 |
=48-12+
| 12 |
| 5 |
=36+
| 12 |
| 5 |
=38
| 2 |
| 5 |
(4)11×11×11-11×11
=11×11×(11-1)
=11×11×10
=121×10
=1210;
(5)
| 9 |
| 10 |
| 5 |
| 8 |
| 1 |
| 8 |
=
| 9 |
| 10 |
| 5 |
| 8 |
| 1 |
| 8 |
=
| 9 |
| 10 |
| 3 |
| 4 |
=
| 3 |
| 20 |
(6)
| 1 |
| 2 |
| 1 |
| 6 |
| 1 |
| 12 |
| 1 |
| 20 |
| 1 |
| 30 |
=(1-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 6 |
=1-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 6 |
=1-
| 1 |
| 6 |
=
| 5 |
| 6 |
点评:考查了运算定律与简便运算,四则混合运算.注意运算顺序和运算法则,灵活运用所学的运算定律简便计算.
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