题目内容
(2013?龙海市模拟)脱式计算.
0.25×
+2.5%
9.6-11÷7+
×4
+
+
+
+
+
+
+
+
+…+
+…+
+…+
.
0.25×
| 4 |
| 5 |
9.6-11÷7+
| 1 |
| 7 |
| 1 |
| 1 |
| 1 |
| 2 |
| 2 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 2 |
| 3 |
| 3 |
| 3 |
| 2 |
| 3 |
| 1 |
| 3 |
| 1 |
| 2005 |
| 2005 |
| 2005 |
| 1 |
| 2005 |
分析:(1)根据乘法分配律进行计算;
(2)根据乘法分配律和连减的性质进行计算;
(3)根据
=1,
+
+
=2,
+
+
+
+
=3,…
+…+
+…+
=2005,原来的数列就变成了1+2+3+…+2004+2005,然后再根据求和公式进一步解答即可.
(2)根据乘法分配律和连减的性质进行计算;
(3)根据
| 1 |
| 1 |
| 1 |
| 2 |
| 2 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 2 |
| 3 |
| 3 |
| 3 |
| 2 |
| 3 |
| 1 |
| 3 |
| 1 |
| 2005 |
| 2005 |
| 2005 |
| 1 |
| 2005 |
解答:解:(1)0.25×
+2.5%,
=0.25×
+0.025,
=0.25×
+0.25×0.1,
=0.25×(
+0.1),
=0.25×0.9,
=0.225;
(2)9.6-11÷7+
×4,
=9.6-11×
+
×4,
=9.6-(11×
-
×4),
=9.6-
×(11-4),
=9.6-
×7,
=9.6-1,
=8.6;
(3)
+
+
+
+
+
+
+
+
+…+
+…+
+…+
,
=1+2+3+…+2004+2005,
=(1+2005)×2005÷2,
=2006×2005÷2,
=2011015.
| 4 |
| 5 |
=0.25×
| 4 |
| 5 |
=0.25×
| 4 |
| 5 |
=0.25×(
| 4 |
| 5 |
=0.25×0.9,
=0.225;
(2)9.6-11÷7+
| 1 |
| 7 |
=9.6-11×
| 1 |
| 7 |
| 1 |
| 7 |
=9.6-(11×
| 1 |
| 7 |
| 1 |
| 7 |
=9.6-
| 1 |
| 7 |
=9.6-
| 1 |
| 7 |
=9.6-1,
=8.6;
(3)
| 1 |
| 1 |
| 1 |
| 2 |
| 2 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 2 |
| 3 |
| 3 |
| 3 |
| 2 |
| 3 |
| 1 |
| 3 |
| 1 |
| 2005 |
| 2005 |
| 2005 |
| 1 |
| 2005 |
=1+2+3+…+2004+2005,
=(1+2005)×2005÷2,
=2006×2005÷2,
=2011015.
点评:四则运算,先弄清运算顺序,然后再进一步计算即可,能简算的要简算.
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