题目内容
| 脱式计算能简算便要简算 | 20-12÷ | 48048÷12+88 | 8- |
| 9÷( | (1-0.8× | 77× |
解:(1)
÷
×
,
=
×4×
,
=
×
×4,
=
×4,
=2;
(2)20-12÷
,
=20-15,
=5;
(3)48048÷12+88,
=4004+88,
=4092;
(4)8-
÷
-
,
=8-
-
,
=8-(
+
),
=8-4,
=4;
(5)9÷(
-
)×3,
=9÷
×3,
=81×3,
=243;
(6)(1-0.8×
)÷
,
=(1-
)÷
,
=
,
=
;
(7)77×
+23×
,
=(77+23)×
,
=100×
,
=80.
分析:(1)先把除法变成乘法,再运用乘法交换律简算;
(2)先算除法,再算减法;
(3)先算除法,再算加法;
(4)先算除法,再根据连续减去两个数等于减去这两个数的和简算;
(5)先算小括号里面的减法,再算括号外的除法,最后算乘法;
(6)先算小括号里面的乘法,再算小括号里面的减法,最后算括号外的除法;
(7)运用乘法分配律简算.
点评:此题是考查四则混合运算,要仔细观察算式的特点,灵活运用一些定律进行简便计算.
=
=
=
=2;
(2)20-12÷
=20-15,
=5;
(3)48048÷12+88,
=4004+88,
=4092;
(4)8-
=8-
=8-(
=8-4,
=4;
(5)9÷(
=9÷
=81×3,
=243;
(6)(1-0.8×
=(1-
=
=
(7)77×
=(77+23)×
=100×
=80.
分析:(1)先把除法变成乘法,再运用乘法交换律简算;
(2)先算除法,再算减法;
(3)先算除法,再算加法;
(4)先算除法,再根据连续减去两个数等于减去这两个数的和简算;
(5)先算小括号里面的减法,再算括号外的除法,最后算乘法;
(6)先算小括号里面的乘法,再算小括号里面的减法,最后算括号外的除法;
(7)运用乘法分配律简算.
点评:此题是考查四则混合运算,要仔细观察算式的特点,灵活运用一些定律进行简便计算.
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