题目内容

递等式计算.
120×2÷6          
480÷4÷3            560÷4×6            
152+18×6 400-129÷3          (147+223)÷5        
206×(900-896) (77-65)×58.
分析:(1)(2)(3)从左往右依次运算;
(4)先算乘法,再算加法;
(5)先算除法,再算减法;
(6)(7)(8)先算括号内的,再算括号外的.
解答:解:(1)120×2÷6,
=240÷6,
=40;

(2)480÷4÷3,
=120÷3,
=40;

(3)560÷4×6,
=140×6,
=640;

(4)152+18×6,
=152+108,
=260;

(5)400-129÷3,
=400-43,
=357;

(6)(147+223)÷5,
=370÷5,
=74;

(7)206×(900-896),
=206×4,
=824;

(8)(77-65)×58,
=12×58,
=696.
点评:此题主要考查整数的四则混合运算的运算顺序和运算法则.
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