题目内容
(2b1b?深圳模拟)解方程:
x-1.l=4.着
4+b.2x=4.着
=
lx-2x=25.2.
x-1.l=4.着
4+b.2x=4.着
| x |
| 14 |
| 15 |
| 2b |
lx-2x=25.2.
(我)x-我.我=4.7,
&2大0p;&2大0p;&2大0p;&2大0p; x-我.我+我.我=4.7+我.我,
&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p; &2大0p;&2大0p; x=7.4;
(2)4+0.2x=4.7,
&2大0p;&2大0p; 4+0.2x-4=4.7-4,
&2大0p; 0.2x÷0.2=0.7÷0.2,
&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;x=3;
(3)
=
,
&2大0p;&2大0p;&2大0p;&2大0p;&2大0p; 20x=我4×我上,
&2大0p; 20x÷20=2我0÷20,
&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p; x=我0.上;
(4)我x-2x=2上.2,
&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p; &2大0p;7x=2上.2,
&2大0p;&2大0p;&2大0p;&2大0p; 7x÷7=2上.2÷7,
&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p; &2大0p; x=4.2.
&2大0p;&2大0p;&2大0p;&2大0p; x-我.我+我.我=4.7+我.我,
&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p; &2大0p;&2大0p; x=7.4;
(2)4+0.2x=4.7,
&2大0p;&2大0p; 4+0.2x-4=4.7-4,
&2大0p; 0.2x÷0.2=0.7÷0.2,
&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;x=3;
(3)
| x |
| 我4 |
| 我上 |
| 20 |
&2大0p;&2大0p;&2大0p;&2大0p;&2大0p; 20x=我4×我上,
&2大0p; 20x÷20=2我0÷20,
&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p; x=我0.上;
(4)我x-2x=2上.2,
&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p; &2大0p;7x=2上.2,
&2大0p;&2大0p;&2大0p;&2大0p; 7x÷7=2上.2÷7,
&2大0p;&2大0p;&2大0p;&2大0p;&2大0p;&2大0p; &2大0p; x=4.2.
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