题目内容
简算与计算
3600000÷125÷32÷25 1.25×6.78+25×3.47+125×0.0382
.
解:(1)3600000÷125÷32÷25,
=3600000÷125÷(4×8)÷25,
=3600000÷(125×8)÷(4×25),
=3600000÷1000÷100,
=36;
(2)1.25×6.78+25×3.47+125×0.0382,
=1.25×6.78+(25÷20)×(3.47×20)+(125÷100),
=1.25×6.78+1.25×69.4+1.25×3.82,
=1.25×(6.78+3.82+69.4),
=1.25×80,
=100;
(3)
,
=
,
=
,
=
,
=1;
(4)
,
=
,
=
,
=
,
=
.
分析:(1)根据除法的性质简算;
(2)先根据积不变规律化简,再运用乘法分配律简算;
(3)先运用乘法分配律把分母化简,再约分求解;
(4)先求出分子的和,再把分子分解成6×6,然后约分求解.
点评:完成本题要注意分析式中数据,运用合适的简便方法计算.
=3600000÷125÷(4×8)÷25,
=3600000÷(125×8)÷(4×25),
=3600000÷1000÷100,
=36;
(2)1.25×6.78+25×3.47+125×0.0382,
=1.25×6.78+(25÷20)×(3.47×20)+(125÷100),
=1.25×6.78+1.25×69.4+1.25×3.82,
=1.25×(6.78+3.82+69.4),
=1.25×80,
=100;
(3)
=
=
=
=1;
(4)
=
=
=
=
分析:(1)根据除法的性质简算;
(2)先根据积不变规律化简,再运用乘法分配律简算;
(3)先运用乘法分配律把分母化简,再约分求解;
(4)先求出分子的和,再把分子分解成6×6,然后约分求解.
点评:完成本题要注意分析式中数据,运用合适的简便方法计算.
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