题目内容
计算
(1)(-12)×1
(2)-0.00125×(-1
)
(3)-(-24)×|-6|
(4)(-4)×(-8)-(-9)×
(5)(-7)×(-0.35)×0
(6)(-
+
-
)×(-48)
(7)(-0.4)÷0.02
(8)(-3
)×(-2
)
(9)(-5
)÷(-16)÷(-2)
(1)(-12)×1
(2)-0.00125×(-1
| 3 |
| 5 |
(3)-(-24)×|-6|
(4)(-4)×(-8)-(-9)×
| 2 |
| 3 |
(5)(-7)×(-0.35)×0
(6)(-
| 1 |
| 6 |
| 3 |
| 4 |
| 1 |
| 12 |
(7)(-0.4)÷0.02
(8)(-3
| 1 |
| 2 |
| 1 |
| 3 |
(9)(-5
| 1 |
| 3 |
分析:(1)负数与正数相乘得负数;
(2)把小数化为分数,约分计算,根据同号得正,异号得负,结果应为负数;
(3)先求出-(-24)=24,然后根据负数的绝对值等于正数,则|-6|=6;
(4)先算乘法,两数相乘,同号得正,异号得负,再算减法;
(5)任何数和0相乘都得0;
(6)运用乘法分配律简算,同时注意运算符号;
(7)先确定商的符号,再算0.4÷0.02;
(8)先确定积的符号:负负得正,再算3
×2
;
(9)先确定商的符号为负数,把除法改为乘法,进行计算.
(2)把小数化为分数,约分计算,根据同号得正,异号得负,结果应为负数;
(3)先求出-(-24)=24,然后根据负数的绝对值等于正数,则|-6|=6;
(4)先算乘法,两数相乘,同号得正,异号得负,再算减法;
(5)任何数和0相乘都得0;
(6)运用乘法分配律简算,同时注意运算符号;
(7)先确定商的符号,再算0.4÷0.02;
(8)先确定积的符号:负负得正,再算3
| 1 |
| 2 |
| 1 |
| 3 |
(9)先确定商的符号为负数,把除法改为乘法,进行计算.
解答:解:(1)(-12)×1=-12;
(2)-0.00125×(-1
),
=0.00125×1
,
=
×
,
=
;
(3)-(-24)×|-6|,
=24×6,
=144;
(4)(-4)×(-8)-(-9)×
,
=32+6,
=38;
(5)(-7)×(-0.35)×0=0;
(6)(-
+
-
)×(-48),
=(-
)×(-48)+
×(-48)+(-
)×(-48),
=8-36+4,
=12-36,
=-24;
(7)(-0.4)÷0.02,
=-(0.4÷0.02),
=-20;
(8)(-3
)×(-2
),
=
×
,
=
;
(9)(-5
)÷(-16)÷(-2),
=(-
)×(-
)×(-
),
=-
×
×
,
=-
.
(2)-0.00125×(-1
| 3 |
| 5 |
=0.00125×1
| 3 |
| 5 |
=
| 1 |
| 800 |
| 8 |
| 5 |
=
| 1 |
| 500 |
(3)-(-24)×|-6|,
=24×6,
=144;
(4)(-4)×(-8)-(-9)×
| 2 |
| 3 |
=32+6,
=38;
(5)(-7)×(-0.35)×0=0;
(6)(-
| 1 |
| 6 |
| 3 |
| 4 |
| 1 |
| 12 |
=(-
| 1 |
| 6 |
| 3 |
| 4 |
| 1 |
| 12 |
=8-36+4,
=12-36,
=-24;
(7)(-0.4)÷0.02,
=-(0.4÷0.02),
=-20;
(8)(-3
| 1 |
| 2 |
| 1 |
| 3 |
=
| 7 |
| 2 |
| 7 |
| 3 |
=
| 49 |
| 6 |
(9)(-5
| 1 |
| 3 |
=(-
| 16 |
| 3 |
| 1 |
| 16 |
| 1 |
| 2 |
=-
| 16 |
| 3 |
| 1 |
| 16 |
| 1 |
| 2 |
=-
| 1 |
| 6 |
点评:此题考查了正负数的乘法和除法,在计算时,应根据乘法和除法法则进行.
练习册系列答案
相关题目