题目内容
(2007?淮安模拟)下面各题怎样简便就怎样计算.
| 3.2×2.5×12.5 | 0.25÷(
| ||||||||
7÷〔
|
5.7×0.25+6.8×25%-8.5×
|
分析:(1)把3.2分成4×0.8,再根据乘法结合律和交换律进行计算,
(2)根据四则运算的计算顺序进行计算,
(3)先算小括号里的,再算中括号里面的,最后求商,
(4)根据乘法分配律进行计算.
(2)根据四则运算的计算顺序进行计算,
(3)先算小括号里的,再算中括号里面的,最后求商,
(4)根据乘法分配律进行计算.
解答:解:(1)3.2×2.5×12.5,
=4×0.8×2.5×12.5,
=(4×2.5)×(0.8×12.5),
=10×10,
=100,
(2)0.25÷(
+0.2)-
,
=0.25÷1-
,
=0.25-0.25,
=0,
(3)7÷〔
×(
+
)〕,
=7÷[
×
],
=7÷
,
=21,
(4)5.7×0.25+6.8×25%-8.5×
,
=5.7×0.25+6.8×0.25-8.5×0.25,
=(5.7+6.8-8.5)×0.25,
=4×0.25,
=1.
=4×0.8×2.5×12.5,
=(4×2.5)×(0.8×12.5),
=10×10,
=100,
(2)0.25÷(
| 4 |
| 5 |
| 1 |
| 4 |
=0.25÷1-
| 1 |
| 4 |
=0.25-0.25,
=0,
(3)7÷〔
| 4 |
| 11 |
| 3 |
| 4 |
| 1 |
| 6 |
=7÷[
| 4 |
| 11 |
| 11 |
| 12 |
=7÷
| 1 |
| 3 |
=21,
(4)5.7×0.25+6.8×25%-8.5×
| 1 |
| 4 |
=5.7×0.25+6.8×0.25-8.5×0.25,
=(5.7+6.8-8.5)×0.25,
=4×0.25,
=1.
点评:本题主要考查了学生四则运算的计算能力,以及在计算中灵活运用简便算法的计算能力.
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