一辆汽车以10m/s的速度匀速前进,制动后,加速度大小为2.5m/s2,问:3s内的位移大小和10 s内的位移大小.                                                                                                                   

下面是某同学的解答过程:                                                                                          

s1=v0t1+at12=[10×3+×(﹣2.5)×32]m=19.65m                                                           

s2=v0t2+at22=[10×10+×(﹣2.5)×102]m=﹣25m                                                         

你认为该同学的解答正确吗?如果你认为正确,请定性说明理由;如果你认为不正确,请说明理由并求出正确结果.                                                                                                                                    

                                                                                                                                    

 0  122708  122716  122722  122726  122732  122734  122738  122744  122746  122752  122758  122762  122764  122768  122774  122776  122782  122786  122788  122792  122794  122798  122800  122802  122803  122804  122806  122807  122808  122810  122812  122816  122818  122822  122824  122828  122834  122836  122842  122846  122848  122852  122858  122864  122866  122872  122876  122878  122884  122888  122894  122902  176998 

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网