一辆汽车以10m/s的速度匀速前进,制动后,加速度大小为2.5m/s2,问:3s内的位移大小和10 s内的位移大小.                                                                                                                   

下面是某同学的解答过程:                                                                                          

s1=v0t1+at12=[10×3+×(﹣2.5)×32]m=19.65m                                                           

s2=v0t2+at22=[10×10+×(﹣2.5)×102]m=﹣25m                                                         

你认为该同学的解答正确吗?如果你认为正确,请定性说明理由;如果你认为不正确,请说明理由并求出正确结果.                                                                                                                                    

                                                                                                                                    

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