ÌâÄ¿ÄÚÈÝ

14£®Ä³Í¬Ñ§Òª²âÁ¿Ò»¸ùСÊԹܵÄÉî¶È²¢´ÖÂÔÈ·¶¨ÆäÖØÐĵÄλÖã®
¢ÙÓÃ20·Ö¶ÈÓα꿨³ß²âÁ¿Éî¶Èʱ£¬Ó¦¸ÃÓÃͼ¼×ËùʾµÄC£¨Ñ¡Ìî¡°A¡±¡¢¡°B¡±»ò¡°C¡±£©²¿Î»½øÐвâÁ¿£»²âÁ¿½á¹ûÈçͼÒÒËùʾ£¬¶ÁÊýΪ81.50mm£®
¢ÚÓÃͼ±ûËùʾµÄ×°ÖôÖÂÔÈ·¶¨ÖÐÐĵÄλÖ㬲½ÖèÈçÏ£º
a£®ÓÃ×ã¹»³¤µÄϸÏß°ÑСÊÔ¹ÜÐü¹ÒÆðÀ´£¬×ö³ÉÒ»¸ö¡°µ¥°Ú¡±£»
b£®Óÿ̶ȳ߲â³öϸÏߵij¤¶ÈL£»
c£®Èá°µ¥°Ú¡±ÔÚijһÊúÖ±ÃæÄÚ×öС½Ç¶ÈµÄ°Ú¶¯£»
d£®ÓÃÃë±í²â³ö¡°µ¥°Ú¡±Íê³Én´ÎÈ«Õñ¶¯µÄ×Üʱ¼ät£»ÔòСÊԹܵÄÖÐÐĵ½¹Ü¿ÚµÄ¾àÀëd=$\frac{g{t}^{2}}{4{¦Ð}^{2}{n}^{2}}-L$£¨ÓÃËù¸øµÄ×Öĸ·ûºÅ±íʾ£¬ÒÑÖªµ±µØµÄÖØÁ¦¼ÓËÙ¶ÈΪg£©£®

·ÖÎö ²âÁ¿Éî¶ÈÓ¦¸ÃÓÃÓα꿨³ßµÄÉî¶È³ß²âÁ¿£»Óα꿨³ßµÄ¶ÁÊýµÈÓÚÖ÷³ß¶ÁÊý¼ÓÉÏÓαê¶ÁÊý£¬²»Ðè¹À¶Á£®
¸ù¾Ýµ¥°ÚµÄÖÜÆÚ¹«Ê½£¬½áºÏÖÜÆÚµÄ´óСÇó³ö°Ú³¤£¬´Ó¶øµÃ³öСÊԹܵÄÖÐÐĵ½¹Ü¿ÚµÄ¾àÀ룮

½â´ð ½â£º¢Ù²âÁ¿Éî¶È£¬Ó¦¸ÃÓÃÉî¶È³ß£¬¼´C²¿Î»²âÁ¿£®
Óα꿨³ßµÄÖ÷³ß¶ÁÊýΪ81mm£¬Óαê¶ÁÊýΪ0.05¡Á10mm=0.50mm£¬Ôò¶ÁÊýΪ81.50mm£®
¢Úµ¥°ÚµÄÖÜÆÚT=$\frac{t}{n}$£¬¸ù¾ÝÖÜÆÚ¹«Ê½T=$2¦Ð\sqrt{\frac{l}{g}}$µÃ°Ú³¤Îªl=$\frac{g{T}^{2}}{4{¦Ð}^{2}}=\frac{g{t}^{2}}{4{¦Ð}^{2}{n}^{2}}$£¬ÔòСÊԹܵÄÖÐÐĵ½¹Ü¿ÚµÄ¾àÀëd=l-L=$\frac{g{t}^{2}}{4{¦Ð}^{2}{n}^{2}}-L$£®
¹Ê´ð°¸Îª£º¢ÙC£¬81.50£¬¢Ú$\frac{g{t}^{2}}{4{¦Ð}^{2}{n}^{2}}-L$£®

µãÆÀ ½â¾ö±¾ÌâµÄ¹Ø¼üÕÆÎÕµ¥°ÚµÄÖÜÆÚ¹«Ê½£¬ÖªµÀ°Ú³¤µÈÓÚÐüµãµ½ÊÔ¹ÜÖÐÐĵľàÀë£¬ÕÆÎÕÓα꿨³ßµÄ¶ÁÊý·½·¨£¬×¢Òâ²»ÐèÒª¹À¶Á£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø