题目内容

如图4-2-13所示,AB的重力分别是40 N和100 N,滑轮的摩擦及绳的质量均不计,B与水平面间的最大静摩擦力为40 N.则B受地面的静摩擦力为_______N,B受地面的支持力为_______N.给B加水平向左的拉力,使B恰好开始滑动,则拉力大小为_______N.

解析:对B受力分析如图.

Ff=FTcos53°                                                                                                     ①

FT=mAg                                                                                                                  

由①②得Ff=24 N

FN+FTsin53°=mBg                                                                                                        

由②③得FN=68 N.

B刚要向左滑动,摩擦力为最大静摩擦力,且方向水平向右,则

F=Ffmax+FTcos53°                                                                                                  ④

由②④得:F=64 N.

答案:24  68  64

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