ÌâÄ¿ÄÚÈÝ

1£®Ò»¸öÓÐÒ»¶¨ºñ¶ÈµÄÔ²ÅÌ£¬¿ÉÒÔÈÆÍ¨¹ýÖÐÐÄ´¹Ö±ÓÚÅÌÃæµÄˮƽÖáת¶¯£¬Ô²Å̼ÓËÙת¶¯Ê±£¬½ÇËٶȵÄÔö¼ÓÁ¿¡÷¦ØÓë¶ÔӦʱ¼ä¡÷tµÄ±ÈÖµ¶¨ÒåΪ½Ç¼ÓËٶȦ£®ÎÒÃÇÓõç´Å´òµã¼ÆÊ±Æ÷¡¢Ã׳ߡ¢Óα꿨³ß¡¢Ö½´ø¡¢¸´Ð´Ö½À´Íê³ÉÏÂÊöʵÑ飺£¨´òµã¼ÆÊ±Æ÷Ëù½Ó½»Á÷µçµÄƵÂÊΪ50Hz£¬A¡¢B¡¢C¡¢D¡­Îª¼ÆÊýµã£¬ÏàÁÚÁ½¼ÆÊýµã¼äÓÐËĸöµãδ»­³ö£©

¢ÙÈçͼ¼×Ëùʾ£¬½«´òµã¼ÆÊ±Æ÷¹Ì¶¨ÔÚ×ÀÃæÉÏ£¬½«Ö½´øµÄÒ»¶Ë´©¹ý´òµã¼ÆÊ±Æ÷µÄÏÞλ¿×£¬È»ºó¹Ì¶¨ÔÚÔ²Å̵IJàÃæ£¬µ±Ô²ÅÌת¶¯Ê±£¬Ö½´ø¿ÉÒÔ¾íÔÚÔ²Å̲àÃæÉÏ£»
¢Ú½ÓͨµçÔ´£¬´òµã¼ÆÊ±Æ÷¿ªÊ¼´òµã£¬Æô¶¯¿ØÖÆ×°ÖÃʹԲÅÌÔȼÓËÙת¶¯£»
¢Û¾­¹ýÒ»¶Îʱ¼ä£¬Ô²ÅÌֹͣת¶¯ºÍ´òµã£¬È¡ÏÂÖ½´ø£¬½øÐвâÁ¿£®
£¨1£©ÈçͼÒÒËùʾ£¬Ô²Å̵ÄÖ±¾¶dΪ4.00cm£»
£¨2£©ÓÉͼ±û¿ÉÖª£¬´òϼÆÊýµãDʱ£¬Ô²ÅÌת¶¯µÄ½ÇËÙ¶ÈΪ1.945rad/s£®
£¨3£©½Ç¼ÓËÙ¶ÈÊǽÇËٶȱ仯µÄ¿ìÂý£¬ÔòÔ²ÅÌת¶¯µÄ½Ç¼ÓËٶȦ´óСΪ29.5rad/s2£®

·ÖÎö £¨1£©¿Ì¶È³ßµÄ¶ÁÊýÐè¶Áµ½×îС¿Ì¶ÈµÄÏÂһλ£®
£¨2£©¸ù¾Ýƽ¾ùËٶȵÈÓÚÖмäʱ¿Ì˲ʱËÙ¶ÈÇó³öDµãµÄ˲ʱËÙ¶È£¬È»ºó¸ù¾Ýv=¦ØrÇó½â½ÇËÙ¶È£»
£¨3£©ÓÃÖð²î·¨Çó½â³ö¼ÓËÙ¶È£¬ÔÙ¸ù¾Ý¼ÓËٶȵÈÓڽǼÓËÙ¶ÈÓë°ë¾¶µÄ³Ë»ýÀ´¼ÆËã½Ç¼ÓËÙ¶È£¬´Ó¶ø¼´¿ÉÇó½â£®

½â´ð ½â£º£¨1£©ÓÉͼ¿ÉÖª£¬Ô²Å̵ÄÖ±¾¶d=6.00-2.00cm=4.00cm£®
£¨2£©DµãµÄ˲ʱËÙ¶È${v}_{D}=\frac{{x}_{CE}}{2T}=\frac{0.1319-0.0541}{0.2}m/s$=0.389m/s£¬ÔòÔ²ÅÌת¶¯µÄ½ÇËÙ¶È$¦Ø=\frac{{v}_{D}}{r}=\frac{0.389}{0.02}=1.945rad/s$£®
£¨3£©¸ù¾Ý¡÷x=aT2£¬ÔËÓÃÖð²î·¨µÃ£¬a=$\frac{{x}_{CE}-{x}_{AC}}{4{T}^{2}}$=$\frac{£¨0.1319-0.0541£©-0.0541}{4¡Á0.01}$=0.59m/s2£¬
½Ç¼ÓËÙ¶È$¦Ñ=\frac{¡÷¦Ø}{¡÷t}$£¬$¦Ø=\frac{v}{r}$£¬¿ÉÖª$¦Â=\frac{a}{r}=\frac{0.59}{0.02}=29.5rad/{s}^{2}$£®
¹Ê´ð°¸Îª£º£¨1£©4.00£¬£¨2£©1.945£¬£¨3£©29.5£®

µãÆÀ ±¾Ìâ¸ù¾Ý¸ù¾ÝÌâÒâÖнǼÓËٶȵ͍Ò壬ͬʱ½áºÏÖ½´ø´¦ÀíÖмÓËٶȺÍËٶȵÄÇ󷨽øÐзÖÎö´¦Àí

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
12£®Èçͼ¼×ËùʾµÄ×°ÖÃÓÉÆøµæµ¼¹ì¡¢Á½¸ö¹âµçÃÅ¡¢»¬¿éºÍɳͰµÈ×é³É£®¹âµçÃÅ¿ÉÒÔ²â³ö»¬¿é·Ö±ðͨ¹ýÁ½¸ö¹âµçÃŵÄʱ¼ä¡÷t1ºÍ¡÷t2£¬µ¼¹ì±ê³ß¿ÉÒÔ²â³öÁ½¸ö¹âµçÃżäµÄ¾àÀëL£¬Óα꿨³ß²âÁ¿ÕÚ¹âÆ¬µÄ¿í¶Èd£¬ÁíÓÃÌìÆ½²â³ö»¬¿éºÍɳÓëɳͰµÄÖÊÁ¿·Ö±ðΪMºÍm£¬»Ø´ðÏÂÁÐÎÊÌ⣺

¢Ù²âÁ¿dʱ£¬Ä³´ÎÓα꿨³ß£¨Ö÷³ßµÄ×îС·Ö¶ÈΪ1mm£©µÄʾÊýÈçͼÒÒËùʾ£¬Æä¶ÁÊýΪ11.30 mm£®
¢ÚÈôÓøÃ×°ÖÃÀ´Ñé֤ţ¶ÙµÚ¶þ¶¨ÂÉ£¬ÒÔÏÂ˵·¨²»ÕýÈ·µÄÊÇA£®
A£®¸Ã×°ÖÿÉÒÔ²»Æ½ºâĦ²ÁÁ¦Ò²²»ÐèÒª½«Æøµæµ¼¹ìµ÷½Úˮƽ
B£®Èç¹ûÆøµæµ¼¹ìˮƽÔòÇáÍÆ»¬¿éÔÈËÙ»¬¶¯Ê±£¬Í¨¹ýÁ½¸ö¹âµçÃŵÄʱ¼ä¡÷t1ºÍ¡÷t2±ØÏàµÈ
C£®ÊµÑéʱ£¬¶à´ÎÔÚͬһÌõ¼þÏÂÖØ¸´ÊµÑéÈ¡µ²¹âƬͨ¹ýÁ½¹âµçÃÅʱ¼äµÄƽ¾ùÖµÒÔ¼õСżȻÎó²î
¢ÛÈôÓôË×°ÖÃÖл¬¿éÊܵ½ÏßµÄÀ­Á¦¼´ºÏÍâÁ¦F ¿ÉÓÃM¡¢m¡¢LºÍʱ¼ä¡÷t1ºÍ¡÷t2±íʾΪF=$M\frac{{£¨\frac{d}{¡÷{t}_{2}}£©}^{2}-{£¨\frac{d}{¡÷{t}_{1}}£©}^{2}}{2L}$£®
¢Üͨ¹ý¼ÆËã±È½Ï·¢ÏÖ»¬¿éÊܵ½µÄÏßµÄÀ­Á¦FÓëɳºÍɳͰµÄÖØÁ¦²»ÏàµÈÇÒÏà²î½Ï´ó£¬ÊÇÒòΪ²»Âú×ãM£¾£¾m£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø