ÌâÄ¿ÄÚÈÝ

3£®Ä³ÎïÀíÐËȤС×éÔÚÀûÓõ¥°Ú²âÖØÁ¦¼ÓËٶȵÄʵÑéÖУº

£¨1£©ËûÃÇÓÃÓα꿨³ß²âÁ¿°ÚÇòµÄÖ±¾¶£¬²âÁ¿½á¹ûÈçͼ1Ëùʾ£¬Ôò¸Ã°ÚÇòµÄÖ±¾¶Îª1.52cm£»
£¨2£©ËûÃDzⶨÁËn´ÎÈ«Õñ¶¯µÄʱ¼äÈçͼ2ÖÐÍ£±íËùʾ£¬ÄÇôͣ±í¶ÁÊýÊÇ67.4s£»
£¨3£©ËûÃDzâÁ¿³ö¶à×éÖÜÆÚT¡¢°Ú³¤LÊýÖµºó£¬ÀûÓüÆËã»úÈí¼þ»­³öT2-LͼÏ󣬲¢ÄâºÏµÃµ½¸ù¾Ý¸ÃͼÏߵķ½³Ì
ΪT2=4.04L+3.5£»ÇëÄã°ïËûÃÇËã³öµ±µØµÄÖØÁ¦¼ÓËٶȵĴóСg=9.76m/s2£¨È¡¦Ð2=9.86£¬¼ÆËã½á¹û±£Áô3λÓÐЧÊý×Ö£©

·ÖÎö £¨1£©Óα꿨³ßµÄ¶ÁÊýµÈÓÚÖ÷³ß¶ÁÊý¼ÓÉÏÓαê¶ÁÊý£¬²»Ðè¹À¶Á£»
£¨2£©Ãë±íµÄ¶ÁÊýµÈÓÚСÅ̶ÁÊý¼ÓÉÏ´óÅ̶ÁÊý£®
£¨3£©¸ù¾Ýµ¥°ÚµÄÖÜÆÚ¹«Ê½µÃ³öT2-LµÄ¹ØÏµÊ½£¬

½â´ð ½â£º£¨1£©Óα꿨³ßµÄÖ÷³ß¶ÁÊýΪ15mm£¬Óαê¶ÁÊýΪ2¡Á0.1mm=0.2mm£¬Ôò°ÚÇòµÄÖ±¾¶d=15.2mm=1.52cm£®
£¨2£©Ãë±íµÄСÅ̶ÁÊýΪ60s£¬´óÅ̶ÁÊýΪ7.4s£¬ÔòÍ£±í¶ÁÊýΪ67.4s£®
£¨3£©¸ù¾Ý$T=2¦Ð\sqrt{\frac{L}{g}}$µÃ£º${T}^{2}=\frac{4{¦Ð}^{2}L}{g}$£¬½áºÏT2=4.04L+3.5Öª£º$\frac{4{¦Ð}^{2}}{g}=4.04$£¬½âµÃ£ºg=$\frac{4{¦Ð}^{2}}{4.04}=\frac{4¡Á9.86}{4.04}=9.76m/{s}^{2}$£®
¹Ê´ð°¸Îª£º£¨1£©1.52£¬£¨2£©67.4£¬£¨3£©9.76£®

µãÆÀ ³£¹æÆ÷²ÄµÄ¶ÁÊýÐèÒªÕÆÎÕ£¬±ÈÈ磺Óα꿨³ß¡¢ÂÝÐý²â΢Æ÷¡¢Ãë±í¡¢¿Ì¶È³ß¡¢µ¯»É³Ó¡¢¶àÓõç±íµÈ£¬ÖªµÀÄÄЩÐèÒª¹À¶Á£¬ÄÄЩ²»ÐèÒª¹À¶Á£®
ÕÆÎÕµ¥°ÚµÄÖÜÆÚ¹«Ê½£¬²¢ÄܱäÐÎÔËÓ㬻ù´¡Ì⣮

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø