Question

站台上有一观察者，在火车开动时站在第1节车厢前端的附近，第1节车厢在5 s内驶过此人．设火车做匀加速运动，求第10节车厢驶过此人需多长时间?

Answer 1

0.81 s

解析：设每节车厢长为x₀，根据x=v₀t+at²有：x₀=at₁₀²                        ①

10x₀=at₁₀²                                                                                         ②

9x₀=at₉²                                                                                             ③

Δt=t₁₀-t₉                                                                                                 ④

联立①②③④式解得：Δt=（）t₁=0.81 s．