ÌâÄ¿ÄÚÈÝ

5£®°ë¾¶ÎªRµÄˮƽԲ̨£¬¿ÉÈÆÍ¨¹ýÔ²ÐÄOµÄÊúÖ±¹â»¬Ï¸ÖáCC¡äת¶¯£¬ÈçͼËùʾ£¬Ô²Ì¨ÉÏÑØÏ໥´¹Ö±µÄÁ½¸ö°ë¾¶·½Ïò¿ÌÓа¼²Û£¬ÖÊÁ¿ÎªmAµÄÎïÌåA·ÅÔÚÒ»¸ö²ÛÄÚ£¬ÎïÌåAÓë²Ûµ×¼äµÄ¶¯Ä¦²ÁÒòÊýΪ¦Ì£¬ÖÊÁ¿ÎªmBµÄÎïÌåB·ÅÔÚÁíÒ»¸ö²ÛÄÚ£¬´Ë²ÛÊǹ⻬µÄ£®AB¼äÓÃÒ»³¤Îªl£¨l£¼R£©ÇÒ²»¿ÉÉ쳤µÄÇáÉþÈÆ¹ýϸÖáÏàÁ¬£®ÒÑ֪Բ̨×öÔÈËÙת¶¯£¬ÇÒA¡¢BÁ½ÎïÌåÏà¶ÔԲ̨²»¶¯£¨A¡¢BÁ½ÎïÌå¿ÉÊÓΪÖʵ㣬ÎïÌåµÄ×î´ó¾²Ä¦²ÁÁ¦½üËÆµÈÓÚ»¬¶¯Ä¦²ÁÁ¦£©£®ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®µ±Ô²Ì¨×ª¶¯µÄ½ÇËÙ¶ÈΪ¦Ø0£¬OAµÄ³¤¶ÈΪl1ʱ£¬AµÄÏòÐÄÁ¦ÎªFA=mA¦Ø02R
B£®ÈôlOA=$\frac{m_B}{{{m_A}+{m_B}}}$l£¬ÔòÎÞÂÛԲ̨ת¶¯µÄ½ÇËÙ¶ÈΪ¶à´ó£¬ÎïÌåAºÍ²ÛÖ®¼äʼÖÕûÓÐĦ²ÁÁ¦
C£®lOA=$\frac{{0.8{m_B}}}{{{m_A}+{m_B}}}$l£¬Ô²Ì¨×ª¶¯µÄ½ÇËٶȦعý´óʱ£¬A±Ø½«Ô¶ÀëOµã
D£®ÈôlOA=$\frac{{0.9{m_B}}}{{{m_A}+{m_B}}}$l£¬Ô²Ì¨×ª¶¯µÄ½ÇËٶȦعý´óʱ£¬B±Ø½«Ô¶ÀëOµã

·ÖÎö ¸ù¾ÝÏòÐÄÁ¦¹«Ê½Çó³öAµÄÏòÐÄÁ¦´óС£¬µ±ÎïÌåAÓë²ÛÖ®¼äûÓÐĦ²ÁÁ¦Ê±£¬Á½ÎïÌå¾ù¿¿À­Á¦ÌṩÏòÐÄÁ¦£¬×¥×¡½ÇËÙ¶ÈÏàµÈ£¬½áºÏÅ£¶ÙµÚ¶þ¶¨Âɵóöת¶¯°ë¾¶µÄ¹ØÏµ£®

½â´ð ½â£ºA¡¢¸ù¾ÝÏòÐÄÁ¦¹«Ê½Öª£¬AµÄÏòÐÄÁ¦${F}_{A}={m}_{A}{l}_{1}{{¦Ø}_{0}}^{2}$£¬¹ÊA´íÎó£®
B¡¢A¡¢Bת¶¯µÄ½ÇËÙ¶ÈÏàµÈ£¬¶ÔBÓУºT=${m}_{B}{l}_{OB}{¦Ø}^{2}$£¬¶ÔA£¬ÈôÎïÌåºÍ²ÛÖ®¼äûÓÐĦ²ÁÁ¦£¬ÔòÓУºT=${m}_{A}{l}_{OA}{¦Ø}^{2}$£¬¿ÉÖªmBlOB=mAlOA£¬lOA+lOB=l£¬½âµÃ${l}_{OA}=\frac{{m}_{B}}{{m}_{A}+{m}_{B}}l$£¬¹ÊBÕýÈ·£®
C¡¢Èô${l}_{OA}£¼\frac{{m}_{B}}{{m}_{A}+{m}_{B}}l$£¬Ô²Ì¨×ª¶¯µÄ½ÇËٶȦعý´óʱ£¬BËùÊܵÄÀ­Á¦²»¹»ÌṩÏòÐÄÁ¦£¬B½«Ô¶ÀëOµã£¬¹ÊC´íÎó£¬DÕýÈ·£®
¹ÊÑ¡£ºBD£®

µãÆÀ ±¾Ìâͨ¹ýÁ¬½ÓÌ忼²éÅ£¶ÙµÚ¶þ¶¨ÂÉ¡¢ÏòÐÄÁ¦¹«Ê½¼°Ä¦²ÁÁ¦£¬½âÌâʱҪעÒâÁ½ÎïÌåת¶¯µÄ½ÇËÙ¶ÈÏàͬ£»Í¬Ê±Òª×¢ÒâÁ½Ð¡ÇòÉþ×ÓµÄÀ­Á¦Ïàͬ£¬½áºÏÅ£¶ÙµÚ¶þ¶¨ÂÉ·ÖÎöÇó½â£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø