ÌâÄ¿ÄÚÈÝ

20£®½«Ò»ÖÊÁ¿ÎªmµÄСÇò´Ó¿ÕÖÐOµãÒÔ³õ¶¯ÄÜEkбÏòÉÏÅ׳ö£¬·ÉÐÐÒ»¶Îʱ¼äºó£¬Ð¡Çòµ½´ï×î¸ßPµãʱËÙ¶Èv ±äΪˮƽ£®²»¼Æ¿ÕÆø×èÁ¦£®Ôò£¨¡¡¡¡£©
A£®Ð¡ÇòÅ׳öʱµÄÊúÖ±·ÖËÙ¶ÈΪ$\sqrt{\frac{2{E}_{k}}{m}-{v}_{0}^{2}}$
B£®´ÓOµãµ½Pµã£¬Ð¡ÇòÉÏÉýµÄ¸ß¶ÈΪ$\frac{{E}_{K}}{mg}$-$\frac{{v}_{0}^{2}}{2g}$
C£®´ÓOµãµ½Pµã¹ý³ÌÖУ¬Ð¡ÇòÔ˶¯µÄƽ¾ùËÙ¶ÈΪ$\frac{{v}_{0}}{2}$+$\sqrt{\frac{{E}_{K}}{2m}}$
D£®´ÓOµãµ½Pµã¹ý³ÌÖУ¬Ð¡ÇòÔ˶¯µÄƽ¾ùËÙ¶ÈΪ$\sqrt{\frac{3{v}_{0}^{2}}{4}+\frac{{E}_{K}}{2m}}$

·ÖÎö бÅ×Ô˶¯ÀàËÆÓÚÆ½Å×Ô˶¯£¬½«Ô˶¯¹ý³Ì·Ö½âΪˮƽµÄÔÈËÙÖ±ÏßÔ˶¯ºÍÊúÖ±·½ÏòµÄÊúÖ±ÉÏÅ×Ô˶¯¼´¿É£¬ÔÙ½áºÏ»úеÄÜÊØºã¶¨Âɼ´¿É½â³ö

½â´ð ½â£ºÐ±Å×Ô˶¯¿ÉÒÔ·Ö½âÎªÑØË®Æ½µÄÔÈËÙÖ±ÏßÔ˶¯ºÍÊúÖ±·½ÏòµÄÊúÖ±ÉÏÅ×Ô˶¯£¬½«OµãËÙ¶È·Ö½âÎªÑØË®Æ½·½ÏòµÄv0£¬ºÍÑØÊúÖ±·½ÏòµÄv1£¬ÈçͼËùʾ
A¡¢Oµã³ö¶¯ÄÜΪEk£¬¸ù¾Ý¶¯Äܹ«Ê½µÃOµãËÙ¶ÈΪ${v}_{O}=\sqrt{\frac{2{E}_{k}}{m}}$£¬¸ù¾Ý¹´¹É¶¨ÀíÓÐ${v}_{1}=\sqrt{\frac{2{E}_{k}}{m}-{v}_{0}^{2}}$£¬AÕýÈ·£»
B¡¢´ÓOÔ˶¯µ½P£¬ÓÉ»úеÄÜÊØºãµÃ$\frac{1}{2}m{v}_{O}^{2}=\frac{1}{2}m{v}_{0}^{2}+mgh$£¬½âµÃh=$\frac{{E}_{k}}{mg}-\frac{{v}_{0}^{2}}{2g}$£¬BÕýÈ·£»
CD¡¢Ë®Æ½·½ÏòµÄÎ»ÒÆx=v0t£¬h=$\frac{1}{2}g{t}^{2}$£¬Ôò${x}_{OP}=\sqrt{{x}^{2}+{h}^{2}}$£¬´ÓOµãµ½Pµã¹ý³ÌÖУ¬Ð¡ÇòÔ˶¯µÄƽ¾ùËÙ¶ÈΪ$\overline{v}=\frac{{x}_{OP}}{t}=\sqrt{\frac{3{v}_{0}^{2}}{4}+\frac{{E}_{k}}{2m}}$£¬¹ÊC´íÎó£¬DÕýÈ·£»
¹ÊÑ¡£ºABD

µãÆÀ бÅ×Ô˶¯µÄ´¦Àí·½·¨ºÍƽÅ×Ô˶¯Ò»Ñù£¬Æäʵ±¾Ìâ¾ÍÊÇÆ½Å×Ô˶¯µÄÄæ¹ý³Ì£¬½«Ô˶¯¹ý³Ì·Ö½â¼´¿É·½±ãÇó½â£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø