ÌâÄ¿ÄÚÈÝ

ͼ5-4Ϊµç±ùÏäµÄ¹¤×÷Ô­ÀíʾÒâͼ.ѹËõ»ú¹¤×÷ʱ£¬Ç¿ÆÈÖÂÀä¼ÁÔÚ±ùÏäÄÚÍâµÄ¹ÜµÀÖв»¶ÏÑ­»·.ÔÚÕô·¢Æ÷ÖÐÖÂÀä¼ÁÆû»¯ÎüÊÕÏäÌåÄÚµÄÈÈÁ¿£¬¾­¹ýÀäÄýÆ÷ʱÖÂÀä¼ÁÒº»¯£¬·Å³öÈÈÁ¿µ½ÏäÌåÍ⣬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨    £©

ͼ5-4

A.ÈÈÁ¿¿ÉÒÔ×Ô·¢µØ´Ó±ùÏäÄÚ´«µ½±ùÏäÍâ

B.µç±ùÏäµÄÖÂÀäϵͳÄܹ»²»¶ÏµØ°Ñ±ùÏäÄÚµÄÈÈÁ¿´«µ½Íâ½ç£¬ÊÇÒòΪÆäÏûºÄÁ˵çÄÜ

C.µç±ùÏäµÄ¹¤×÷Ô­Àí²»Î¥·´ÈÈÁ¦Ñ§µÚÒ»¶¨ÂÉ

D.µç±ùÏäµÄ¹¤×÷Ô­ÀíÎ¥·´ÈÈÁ¦Ñ§µÚÒ»¶¨ÂÉ

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨1£©¶ÔÒ»¶¨Á¿µÄÆøÌ壬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ        

A£®ÆøÌåµÄÌå»ýÊÇËùÓÐÆøÌå·Ö×ÓµÄÌå»ýÖ®ºÍ

B£®ÆøÌå·Ö×ÓµÄÈÈÔ˶¯Ô½¾çÁÒ£¬ÆøÌåζȾÍÔ½¸ß

C£®ÆøÌå¶ÔÆ÷±ÚµÄѹǿÊÇÓÉ´óÁ¿ÆøÌå·Ö×Ó¶ÔÆ÷±Ú²»¶ÏÅöײ¶ø²úÉúµÄ

D£®µ±ÆøÌåÅòÕÍʱ£¬ÆøÌå·Ö×ÓÖ®¼äµÄÊÆÄܼõС£¬Òò¶øÆøÌåµÄÄÚÄܼõÉÙ

£¨2£©ÈçͼËùʾΪµç±ùÏäµÄ¹¤×÷Ô­ÀíʾÒâͼ£®Ñ¹Ëõ»ú¹¤×÷ʱ£¬Ç¿ÆÈÖÆÀä¼ÁÔÚ±ùÏäÄÚÍâµÄ¹ÜµÀÖв»¶ÏÑ­»·£®ÔÚÕô·¢Æ÷ÖÐÖÆÀä¼ÁÆû»¯ÎüÊÕÏäÌåÄÚµÄÈÈÁ¿£¬¾­¹ýÀäÄýÆ÷Ê±ÖÆÀä¼ÁÒº»¯£¬·Å³öÈÈÁ¿µ½ÏäÌåÍ⣮ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ        £®

A£®ÈÈÁ¿¿ÉÒÔ×Ô·¢µØ´Ó±ùÏäÄÚ´«µ½±ùÏäÍâ

B£®µç±ùÏäµÄ¹¤×÷Ô­Àí²»Î¥·´ÈÈÁ¦Ñ§µÚÒ»¶¨ÂÉ

C£®µç±ùÏäµÄ¹¤×÷Ô­ÀíÎ¥·´ÈÈÁ¦Ñ§µÚÒ»¶¨ÂÉ

D£®µç±ùÏäµÄÖÆÀäϵͳÄܹ»²»¶ÏµØ°Ñ±ùÏäÄÚµÄÈÈÁ¿´«µ½Íâ½ç£¬ÊÇÒòΪÆäÏûºÄÁ˵çÄÜ

£¨3£©ÀûÓÃÓÍĤ·¨¿ÉÒÔ´ÖÂÔ²â³ö°¢·ü¼ÓµÂÂÞ³£Êý£¬°ÑÃܶȦѣ½0.8¡Á103 kg/m3µÄijÖÖÓÍ£¬ÓõιܵγöÒ»µÎÔÚË®ÃæÉÏÐγÉÓÍĤ£¬ÒÑÖªÕâµÎÓ͵ÄÌå»ýΪV£½0.5¡Á10£­3 cm3£¬ÐγɵÄÓÍÄ¤Ãæ»ýΪS£½0.7 m2.Ó͵ÄĦ¶ûÖÊÁ¿M£½0.09 kg/mol.Èô°ÑÓÍĤ¿´³ÉÊǵ¥·Ö×Ӳ㣬ÿ¸öÓÍ·Ö×Ó¿´³ÉÇòÐΣ¬Ö»ÐèÒª±£ÁôһλÓÐЧÊý×Ö£¬ÄÇô£º

¢ÙÓÍ·Ö×ÓµÄÖ±¾¶ÊǶàÉÙ£¿

¢ÚÓÉÒÔÉÏÊý¾Ý¿É´ÖÂÔ²â³ö°¢·ü¼ÓµÂÂÞ³£ÊýNAÊǶàÉÙ£¿(ÏÈÁгöÎÄ×Ö¼ÆËãʽ£¬ÔÙ´úÈëÊý¾Ý¼ÆËã)

 

£¨1£©¶ÔÒ»¶¨Á¿µÄÆøÌ壬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ        

A£®ÆøÌåµÄÌå»ýÊÇËùÓÐÆøÌå·Ö×ÓµÄÌå»ýÖ®ºÍ

B£®ÆøÌå·Ö×ÓµÄÈÈÔ˶¯Ô½¾çÁÒ£¬ÆøÌåζȾÍÔ½¸ß

C£®ÆøÌå¶ÔÆ÷±ÚµÄѹǿÊÇÓÉ´óÁ¿ÆøÌå·Ö×Ó¶ÔÆ÷±Ú²»¶ÏÅöײ¶ø²úÉúµÄ

D£®µ±ÆøÌåÅòÕÍʱ£¬ÆøÌå·Ö×ÓÖ®¼äµÄÊÆÄܼõС£¬Òò¶øÆøÌåµÄÄÚÄܼõÉÙ

£¨2£©ÈçͼËùʾΪµç±ùÏäµÄ¹¤×÷Ô­ÀíʾÒâͼ£®Ñ¹Ëõ»ú¹¤×÷ʱ£¬Ç¿ÆÈÖÆÀä¼ÁÔÚ±ùÏäÄÚÍâµÄ¹ÜµÀÖв»¶ÏÑ­»·£®ÔÚÕô·¢Æ÷ÖÐÖÆÀä¼ÁÆû»¯ÎüÊÕÏäÌåÄÚµÄÈÈÁ¿£¬¾­¹ýÀäÄýÆ÷Ê±ÖÆÀä¼ÁÒº»¯£¬·Å³öÈÈÁ¿µ½ÏäÌåÍ⣮ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ         £®

A£®ÈÈÁ¿¿ÉÒÔ×Ô·¢µØ´Ó±ùÏäÄÚ´«µ½±ùÏäÍâ

B£®µç±ùÏäµÄ¹¤×÷Ô­Àí²»Î¥·´ÈÈÁ¦Ñ§µÚÒ»¶¨ÂÉ

C£®µç±ùÏäµÄ¹¤×÷Ô­ÀíÎ¥·´ÈÈÁ¦Ñ§µÚÒ»¶¨ÂÉ

D£®µç±ùÏäµÄÖÆÀäϵͳÄܹ»²»¶ÏµØ°Ñ±ùÏäÄÚµÄÈÈÁ¿´«µ½Íâ½ç£¬ÊÇÒòΪÆäÏûºÄÁ˵çÄÜ

£¨3£©ÀûÓÃÓÍĤ·¨¿ÉÒÔ´ÖÂÔ²â³ö°¢·ü¼ÓµÂÂÞ³£Êý£¬°ÑÃܶȦѣ½0.8¡Á103 kg/m3µÄijÖÖÓÍ£¬ÓõιܵγöÒ»µÎÔÚË®ÃæÉÏÐγÉÓÍĤ£¬ÒÑÖªÕâµÎÓ͵ÄÌå»ýΪV£½0.5¡Á10£­3 cm3£¬ÐγɵÄÓÍÄ¤Ãæ»ýΪS£½0.7 m2.Ó͵ÄĦ¶ûÖÊÁ¿M£½0.09 kg/mol.Èô°ÑÓÍĤ¿´³ÉÊǵ¥·Ö×Ӳ㣬ÿ¸öÓÍ·Ö×Ó¿´³ÉÇòÐΣ¬Ö»ÐèÒª±£ÁôһλÓÐЧÊý×Ö£¬ÄÇô£º

¢ÙÓÍ·Ö×ÓµÄÖ±¾¶ÊǶàÉÙ£¿

¢ÚÓÉÒÔÉÏÊý¾Ý¿É´ÖÂÔ²â³ö°¢·ü¼ÓµÂÂÞ³£ÊýNAÊǶàÉÙ£¿(ÏÈÁгöÎÄ×Ö¼ÆËãʽ£¬ÔÙ´úÈëÊý¾Ý¼ÆËã)

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø