1.已知A(1,3),B(4,-1),则与向量$\overrightarrow{AB}$共线的单位向量为( )
| A. | $({\frac{4}{5},\frac{3}{5}})$或$({-\frac{4}{5},\frac{3}{5}})$ | B. | $({\frac{3}{5},-\frac{4}{5}})$或$({-\frac{3}{5},\frac{4}{5}})$ | C. | $({-\frac{4}{5},-\frac{3}{5}})$或$({\frac{4}{5},\frac{3}{5}})$ | D. | $({-\frac{3}{5},-\frac{4}{5}})$或$({\frac{3}{5},\frac{4}{5}})$ |
20.在△ABC中,D是边AB上的中点,记$\overrightarrow{BC}$=$\overrightarrow{a}$,$\overrightarrow{BA}$=$\overrightarrow{c}$,则向量$\overrightarrow{CD}$=( )
| A. | -$\overrightarrow{a}$-$\frac{1}{2}$$\overrightarrow{c}$ | B. | $\overrightarrow{a}$-$\frac{1}{2}$$\overrightarrow{c}$ | C. | -$\overrightarrow{a}$+$\frac{1}{2}$$\overrightarrow{c}$ | D. | $\overrightarrow{a}$+$\frac{1}{2}$$\overrightarrow{c}$ |
17.若直线x+(2-a)y+1=0与圆x2+y2-2y=0相切,则a的值为( )
| A. | 1或-1 | B. | 2或-2 | C. | 2 | D. | -2 |
16.已知正三棱柱ABC-A1B1C1的六个顶点在球O1上,又知球O2与此正三棱柱的5个面都相切,求球O1与球O2的表面积之比( )
| A. | 5:1 | B. | 2:1 | C. | 4:1 | D. | $\sqrt{3}$:1 |
15.定义运算:$a?b=\left\{\begin{array}{l}a,(a>b)\\ b,(a<b)\end{array}\right.$,例如2?3=3,则下列等式不能成立的是( )
0 238321 238329 238335 238339 238345 238347 238351 238357 238359 238365 238371 238375 238377 238381 238387 238389 238395 238399 238401 238405 238407 238411 238413 238415 238416 238417 238419 238420 238421 238423 238425 238429 238431 238435 238437 238441 238447 238449 238455 238459 238461 238465 238471 238477 238479 238485 238489 238491 238497 238501 238507 238515 266669
| A. | (a?b)2=a2?b2 | B. | (a?b)?c=a?(b?c) | ||
| C. | (a?b)2=(b?a)2 | D. | c•(a?b)=(c•a)?(c•b)(c>0) |